在fortran中使用fgsl:如何使用gfortran进行编译 [英] Use fgsl in fortran: how to compile with gfortran

问题描述

我正在尝试做一些基本的事情，但是我找不到有关如何编译的相关信息.我尝试了以下方法，但均未成功:

I am trying to do something basic, but I can't find the relevant information on how to compile. I tried the following without success:

gfortran testintegral.f90 -lgsl -lgslcblas
testintegral.f90:19.6:
  use fgsl
      1
Fatal Error: Can't open module file 'fgsl.mod' for reading at (1): No such file 

该文件来自 http://de.wikibooks.org/wiki/Fortran:_FGSL#Beispiel:_Numerische_Integration (德语页面，但易于理解)，所以我认为可以.

The file is taken from http://de.wikibooks.org/wiki/Fortran:_FGSL#Beispiel:_Numerische_Integration (page in german but readily understandable) so I suppose it is OK.

也许编译命令的语法不正确?

Maybe the syntax of the compilation command is incorrect ?

我编辑我的第一篇文章，以免在评论中掩盖重要信息.

I edit my initial post so as not to bury important information in the comments.

这些是库的路径:

sudo find -name '*libgsl.so*'
./usr/lib/libgsl.so.0
./usr/lib/libgsl.so.0.17.0
sudo find -name '*libgslcblas.so*'
./usr/lib/libgslcblas.so.0
./usr/lib/libgslcblas.so.0.0.0

但是在执行此操作时，我仍然收到错误消息:

But I still got an error message when doing:

gfortran testintegral.f90 -L/usr/lib -I/usr/include/fgsl -lfgsl -lgsl -lgslcblas
/usr/bin/ld: cannot find -lgsl
/usr/bin/ld: cannot find -lgslcblas
collect2: error: ld returned 1 exit status

推荐答案

使用 -I 标志.例如，

gfortran -I/usr/local/fgsl/include testintegral.f90 -lgsl -lgslcblas

然后包括该目录中的所有.mod文件.

All the .mod files in that directory are then included.

另请参见下面的评论.

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