如何在React.js中将可选元素作为道具传递给组件 [英] How to pass optional elements to a component as a prop in reactjs

问题描述

我正在尝试找出正确的反应"方式，以将作为元素的可选道具传递给容器组件，该组件的处理方式不同于该组件的子组件.

I am trying to figure out the proper "react" way to pass in an optional prop that is an Element to a container component, that is handled differently from the children of that component.

对于一个简单的示例，我有一个Panel组件，该组件呈现其子级，还具有一个可选的"title"属性(为示例起见，它是元素而不是字符串)，该属性专门进行了渲染(放置在一个特殊的位置，并在保持抽象的同时具有特殊的行为.

For a simple example, I have a Panel component, which renders its children, that also has an optional "title" prop (which is an element rather than a string, for the sake of the example) that gets specially rendered (put in a special spot, with special behaviors in while maintaining the abstraction.

一个选择是拥有一个从子级中拉出并专门渲染的组件:

One option is to have a component which is pulled out of the children and rendered specially:

<Panel>
   <Title> some stuff</Title>
   <div> some other stuff</div>
</Panel>

但是，像这样将孩子们拉出来并分开处理似乎很奇怪.

But it seems wierd to have the children pulled out and handled separately like that.

这通常是如何应对的，我什至在想这是正确的方式

How is this normally handled in react, and am I even thinking about this the right way

推荐答案

您无需执行任何特殊操作.只需将标题组件作为道具传递，然后在要渲染的任何地方使用 {this.props.title} :

You don't need to do anything special. Just pass the title component as a prop, and then use {this.props.title} wherever you want it to be rendered:

class Panel extends React.Component {
  render() {
    return <div>
      {this.props.title}
      <div>Some other stuff...</div>
    </div>;
  }
}

class App extends React.Component {
  render() {
    var title = <Title>My Title</Title>;
    return <Panel title={title}/>;
  }
}

如果您未传递 title 道具的任何值(或者该值是 false ， null 或未定义)，那么在那里什么也不会呈现.

If you don't pass any value for the title prop (or if the value is false, null, or undefined) then nothing will be rendered there.

这是React中相当普遍的模式.

This is a fairly common pattern in React.

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