带有Python列表的`not`运算符的怪异行为 [英] Weird behaviour of `not` operator with python list
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问题描述
当我尝试使用python的 not
运算符检查列表是否为空时,它的运行方式很奇怪.
When I'm trying to check whether a list is empty or not using python's not
operator it is behaving in a weird manner.
我尝试将 not
运算符与列表一起使用,以检查其是否为空.
I tried using the not
operator with a list to check whether it is empty or not.
>>> a = []
>>> not (a)
True
>>> not (a) == True
True
>>> not (a) == False
True
>>> True == False
False
not(a)== False
的预期输出应为False.
The expected output for not (a) == False
should be False.
推荐答案
==
具有比 not
更高的优先级. not(a)== False
解析为 not(a == False)
.
==
has higher precedence than not
. not (a) == False
is parsed as not (a == False)
.
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