如何正确计算C中的æøå(Unicode为UTF-8)字符? [英] How to correctly count æ ø å (Unicode as UTF-8) characters in C?

问题描述

我正在编写一个简单的程序，该程序对放在链接列表中的文本文件(UTF-8)中的字符进行计数.一切似乎都运行良好，只是每个实例都计算两次æøå(挪威字母中的最后三个字符).因此，如果字符串是æøå，我得到6而不是3.如何解决这个问题?

I am writing a simple program that counts characters from a textfile (UTF-8) that I put in a linked list. Everything seem to work well except that it counts æ ø å (three last characters in the norwegian alphabet) twice for each instance. So if the string is æøå, I get 6 instead of 3. How to fix this?

int length()
{
  pointer = root; // Reset pointer
  int i; // Looping through data in node 
  int len = 0; // Counting characters
  int sizedata = sizeof(pointer->data); // Sets size limit for data in node

  while(pointer != NULL)
    {
      for(i = 0; i < sizedata; i++) // Looping through data in node
    {
      if(pointer->data[i] == '\0') break; // Stops count on end of string
      len++; // Counting characters
    }
      pointer = pointer->next; // Linking to next node
    }
  printf("Length of text is: %d characters\n", len);
}

推荐答案

我根据注意(感谢@Eljay):这是在计算Unicode代码点(以UTF-8编码)，而不是字符(字形).一些字符由多个代码点组成.例如，对于x和两个组合代码点，x̝̌为78 cc 9d cc 8c.此例程会将那个1个字符算作3个(代码点)的长度.

Note (thanks @Eljay): This is counting Unicode code points (that are encoded in UTF-8), but not characters (glyphs). Some characters are made up of multiple code points. For example, x̝̌ is 78 cc 9d cc 8c, for the x and the two combining code points. This routine would count that 1 character as a length of 3 (code points).

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