cron表达式解析为java date [英] cron expression parsing into java date

问题描述

• 我的数据库具有 10 18 16吗?* SUN，MON，WED，FRI * cron表达式，然后如何将其转换为Java日期.
• 如何与当前时间进行比较.
• 还有一个是如何与cron表达式(即 10 18 16)进行比较?* SUN，MON，WED，FRI * 和 0 30 9 30 *?
• 请解释使用石英或弹簧调度的示例代码.

• my database having 10 18 16 ? * SUN,MON,WED,FRI * cron expression then how to convert into Java date.
• how to comparing with present day time.
• and one more is how to compare to cron expressions i.e. 10 18 16 ? * SUN,MON,WED,FRI * and 0 30 9 30 * ?
• please explain the sample code using quartz or spring scheduling.

推荐答案

请使用:

import org.springframework.scheduling.support.CronSequenceGenerator;

final String cronExpression = "0 45 23 * * *";
final CronSequenceGenerator generator = new CronSequenceGenerator(cronExpression);
final Date nextExecutionDate = generator.next(new Date());

...然后我建议使用Joda DateTime进行日期比较.

...and then I suggest use Joda DateTime for date comparison.

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