当另一个程序使cronjob中的命令失败时，如何使用cronjob? [英] How can I use a cronjob when another program makes the commands in the cronjob fail?

问题描述

我有一个cron作业，将 cd 放入目录并执行操作.

I have a cron job which cd into a directory and performs actions.

例如:

0 12,00 * * * cd /var/lib/test/0001 && cp *.zip /home/bobby/

但是，在/var/lib/test/0001 中创建.zip文件的程序每天都会更改目录名称.因此，第二天的目录为/var/lib/test/0002 ，第三天的目录为/var/lib/test/0003 ，依此类推.该模型无法更改.

However, the program that creates the .zip files in /var/lib/test/0001 changes the directory name every day. So on the second day, the directory is /var/lib/test/0002 and on the third day /var/lib/test/0003 and so on. This model cannot be changed.

当然，当目录从 0001 迁移到 0002 时，cronjob失败.

Of course, when the directory migrates from 0001 to 0002, the cronjob fails.

是否可以使用cron将cd cd 转换为 000 * ，然后转换为 001 * ，依此类推，从而使 cp命令会运行吗?也许有另一种方法?谢谢.

Is there a way to use cron to cd into 000* and then 001* and so on so that the cp command will be run? Perhaps there is an alternative way? Thank you.

3月13日修改:

还有一个我很难解决的问题.

There is another issue that I am finding hard to solve.

我只想对某个文件大小以上的文件进行 cp 个文件.我想将.zip文件复制到超过28,000个字节的/home/bobby/中.如果它们少于28,000个字节，则不会被复制.谢谢，我该怎么办?

I only want to cp files that are above a certain filesize. I want to copy .zip files to /home/bobby/ which are more than 28,000 bytes. If they are less than 28,000 bytes, then they don't get copied. How would I do this, thanks?

和以前一样，这会发生在/var/lib/test/**** 中(其中 **** 来自 0000 为 FFFF 并每天递增).

As before, this would happen in /var/lib/test/**** (where **** goes from 0000 to FFFF and increments every day).

推荐答案

您可以使用示例脚本执行此操作:

You can do this with sample script:

dir=$(ls -tr1 /var/lib/test|tail -1)
cd /var/lib/test/$dir && cp *.zip /home/bobby/

ls 获取按时间反向排序的文件列表，因此最后一个是最后一个目录.然后我们进一步使用它.

ls get the list of files sort by time in reverse order so the last one is the last directory. And then we use it further.

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