在Java中XML请求/响应 [英] XML request/response in Java

问题描述

我有我想要使用来获取数据的API。为了获取数据我要送XML格式和响应的请求将XML发送。没有人有任何例如如何发送使用Java和如何去code在Java中响应的请求。

I have an API which I want to use to fetch data. For fetching data I have to send a request in XML format and response will be sent in XML. Does anyone have any example how to send a request using Java and how to decode the response in java.

推荐答案

嗯，我有你想要的正是...但我会要求您使用以下API ...

Well i have just what you wanted... but i would ask you to use the following APIs ...

• JAXP 和 JAXB


• 蓖麻

• JAXP and JAXB
• Castor

- 以下code段方法接受网​​址 web服务器和 XMLQUERY <的/ code>

- The below code snippet method accepts the url of the web-server and the xmlQuery

- 我已经使用了的NameValuePair <​​/ code>发送XML请求

- I have used the NameValuePair to send the XML request

- 请替换的 MySSLSocketFactory.getNewHttpClient（）; 与 HTTP 客户端，我已经使用这个需要自定义证书访问此site.`

- Please replace the MySSLSocketFactory.getNewHttpClient(); with an Http Client, i have used this it needs a custom certificate to access this site.`

这是从我的项目，发送一个XML REQ和回来一个XML RESP的code：

public String postData(String url, String xmlQuery) {

        final String urlStr = url;
        final String xmlStr = xmlQuery;
        final StringBuilder sb = new StringBuilder();

        Thread t1 = new Thread(new Runnable() {

            public void run() {

                HttpClient httpclient = MySSLSocketFactory.getNewHttpClient();

                HttpPost httppost = new HttpPost(urlStr);

                try {

                    List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(
                            1);
                    nameValuePairs.add(new BasicNameValuePair("xml", xmlStr));

                    httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

                    HttpResponse response = httpclient.execute(httppost);

                    Log.d("Vivek", response.toString());

                    HttpEntity entity = response.getEntity();
                    InputStream i = entity.getContent();

                    Log.d("Vivek", i.toString());
                    InputStreamReader isr = new InputStreamReader(i);

                    BufferedReader br = new BufferedReader(isr);

                    String s = null;

                    while ((s = br.readLine()) != null) {

                        Log.d("YumZing", s);
                        sb.append(s);
                    }

                    Log.d("Check Now", sb + "");

                } catch (ClientProtocolException e) {

                    e.printStackTrace();
                } catch (IOException e) {
                    e.printStackTrace();
                } 
            }

        });

        t1.start();
        try {
            t1.join();
        } catch (InterruptedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        System.out.println("Getting from Post Data Method " + sb.toString());

        return sb.toString();
    }

这篇关于在Java中XML请求/响应的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！