如何编写CSS选择器来选择不具有特定属性的元素? [英] How to write a CSS Selector selecting elements NOT having a certain attribute?

问题描述

如何编写CSS选择器以选择不具有特定属性的元素?

How to write a CSS Selector selecting elements NOT having a certain attribute?

我有2个< div> 节点，如下所示:

I have 2 <div> nodes as follows:

• 第一个:

• First:

<div class="weEq5" style="will-change; width;">
    <button class="_35EW6">

第二个:

Second:

<div class="weEq5">
    <button class="_35EW6">

我需要选择< div> (具有相似的类)，并且每个都有类似的 descending < button> ，但没有 style 属性.

I need to select the <div> (with the similar class) and each of them which have a similar descending <button> but without the style attribute.

XPath 似乎可以正常工作，

//div[@class and not (@style)]/button

我正在寻找等效的 CssSelector .

试用:

div[class :not(style)]>button (doesn't works).

我已经通过以下讨论，但是他们似乎正在将 class 属性作为:not([class])丢弃，如下所示:

I have been through the following discussion but they seem to be discarding the class attribute as :not([class]) as in:

• 我可以写吗一个CSS选择器选择没有特定类的元素?
• 我在寻找以:not(attribute)结尾的类似行.

  I was looking in similar lines ending with :not(attribute).

  推荐答案

  我认为更准确的CSS选择器是:

  I think more accurate CSS Selector is:

  div[class]:not([style])>button
  

  因为 button 元素是 div 元素的子元素.

  because the button element is a child of div element.

  希望它对您有帮助！

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