推力函子:“请求发射的太多资源" [英] thrust functor: "too many resources requested for launch"

问题描述

我正在尝试在CUDA中实现这样的事情:

I'm trying to implement something like this in CUDA:

每个元素

p = { p if p >= floor
      z if p < floor

其中 floor 和 z 是在测试开始时配置的常量.

Where floor and z are constants configured at the start of the test.

我试图像这样实现它，但是出现错误请求启动的资源过多"

I have attempted to implement it like so, but I get the error "too many resources requested for launch"

函子:

struct floor_functor : thrust::unary_function <float, float>
{
        const float floorLevel, floorVal;

        floor_functor(float _floorLevel, float _floorVal) : floorLevel(_floorLevel), floorVal(_floorVal){}

        __host__
        __device__
        float operator()(float& x) const
        {
            if (x >= floorLevel)
                return x;
            else
                return floorVal;
        }
};

由转换使用:

thrust::transform(input->begin(), input->end(), output.begin(), floor_functor(floorLevel, floorVal));

如果我删除函子的一个成员，例如 floorVal ，并且只使用一个成员变量的函子，它将正常工作.

If I remove one of the members of my functor, say floorVal, and use a functor with only one member variable, it works fine.

有人知道为什么会这样吗，我该如何解决?

Does anyone know why this might be, and how I could fix it?

其他信息:

我的数组长786432个元素.

My array is 786432 elements long.

我的GPU是GeForce GTX590

My GPU is a GeForce GTX590

我正在使用以下命令进行构建:

I am building with the command:

`nvcc -c -g -arch sm_11 -Xcompiler -fPIC -Xcompiler -Wall -DTHRUST_DEBUG  -I <my_include_dir> -o <my_output> <my_source>`

我的cuda版本是4.0:

My cuda version is 4.0:

$ nvcc --version
nvcc: NVIDIA (R) Cuda compiler driver
Copyright (c) 2005-2011 NVIDIA Corporation
Built on Thu_May_12_11:09:45_PDT_2011
Cuda compilation tools, release 4.0, V0.2.1221

我每个块的最大线程数是1024(由deviceQuery报告):

And my maximum number of threads per block is 1024 (reported by deviceQuery):

Total amount of constant memory:               65536 bytes
  Total amount of shared memory per block:       49152 bytes
  Total number of registers available per block: 32768
  Warp size:                                     32
  Maximum number of threads per block:           1024
  Maximum sizes of each dimension of a block:    1024 x 1024 x 64
  Maximum sizes of each dimension of a grid:     65535 x 65535 x 65535

更新::

我偶然发现了解决我的问题的方法，但是不明白.如果我将函子从"floor_functor"重命名为其他名称，则它可以正常工作！我不知道为什么会这样，并且想听听任何人对此的想法.

I have stumbled upon a fix for my problem, but do not understand it. If I rename my functor from "floor_functor" to basically anything else, it works! I have no idea why this is the case, and would be interested to hear anyone's ideas about this.

推荐答案

对于更简单的CUDA实现，您可以使用ArrayFire在一行代码中做到这一点:

For an easier CUDA implementation, you could do this with ArrayFire in one line of code:

p(p < floor) = z;

只需将变量声明为af :: array即可.

Just declare your variables as af::array's.

祝你好运！

免责声明:我从事各种CUDA项目，包括ArrayFire.

Disclaimer: I work on all sorts of CUDA projects, including ArrayFire.

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