如何使用Python执行cURL命令? [英] How to use Python to execute a cURL command?

问题描述

我想在Python中执行curl命令.

I want to execute a curl command in Python.

通常，我只需要在终端中输入命令并按回车键即可.但是，我不知道它如何在Python中工作.

Usually, I just need to enter the command in the terminal and press the return key. However, I don't know how it works in Python.

命令显示如下:

curl -d @request.json --header "Content-Type: application/json" https://www.googleapis.com/qpxExpress/v1/trips/search?key=mykeyhere

有一个 request.json 文件要发送以获得响应.

There is a request.json file to be sent to get a response.

我搜索了很多东西，感到很困惑.我尝试编写一段代码，尽管我不能完全理解它，但是它不起作用.

I searched a lot and got confused. I tried to write a piece of code, although I could not fully understand it and it didn't work.

import pycurl
import StringIO

response = StringIO.StringIO()
c = pycurl.Curl()
c.setopt(c.URL, 'https://www.googleapis.com/qpxExpress/v1/trips/search?key=mykeyhere')
c.setopt(c.WRITEFUNCTION, response.write)
c.setopt(c.HTTPHEADER, ['Content-Type: application/json','Accept-Charset: UTF-8'])
c.setopt(c.POSTFIELDS, '@request.json')
c.perform()
c.close()
print response.getvalue()
response.close()

错误消息是 Parse Error .如何正确地从服务器获得响应?

The error message is Parse Error. How to get a response from the server correctly?

推荐答案

为简单起见，也许您应该考虑使用

For sake of simplicity, maybe you should consider using the Requests library.

带有json响应内容的示例如下:

An example with json response content would be something like:

import requests
r = requests.get('https://github.com/timeline.json')
r.json()

如果您需要更多信息，请在快速入门部分中，他们有很多可行的示例.

If you look for further information, in the Quickstart section, they have lots of working examples.

针对特定的卷曲翻译:

import requests
url = 'https://www.googleapis.com/qpxExpress/v1/trips/search?key=mykeyhere'
payload = open("request.json")
headers = {'content-type': 'application/json', 'Accept-Charset': 'UTF-8'}
r = requests.post(url, data=payload, headers=headers)

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