光标位置在TextView中已更改 [英] Cursor position changed in textview
本文介绍了光标位置在TextView中已更改的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
在PyGTK中,无论何时将光标移到我的应用程序的textview中,我都希望获得光标的当前位置.因此,我需要创建一个回调函数并连接到信号.但是我不确定从哪里得到该信号.
In PyGTK, I want to get the current position of the cursor whenever the cursor is moved inside a textview in my app. So I need to create a callback function and connect to a signal. But I'm not sure from where to get that signal.
推荐答案
您要监视缓冲区的cursor-position属性,请查看下面的示例以监视光标位置.
You want to monitor the cursor-position property of the buffer, look at the example here below for monitoring the cursor position.
from gi.repository import Gtk
class CursorSample(Gtk.Application):
def __init__(self):
Gtk.Application.__init__(self, application_id="org.app.CursorSample")
self.buffer = Gtk.TextBuffer()
self.buffer.connect("notify::cursor-position",
self.on_cursor_position_changed)
self.tw = Gtk.TextView()
self.tw.set_buffer(self.buffer)
self.tw.props.wrap_mode = Gtk.WrapMode.CHAR
def do_activate(self):
main_window = Gtk.Window(Gtk.WindowType.TOPLEVEL)
main_window.add(self.tw)
self.add_window(main_window)
main_window.set_position(Gtk.WindowPosition.CENTER)
main_window.show_all()
def on_cursor_position_changed(self, buffer, data=None):
print buffer.props.cursor_position
if __name__ == "__main__":
cursorsample = CursorSample()
cursorsample.run(None)
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