从每小时数据中找到每天的最大值 [英] Find maximum value of each day from hourly data

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问题描述

我无法从每小时数据中获取每天的最大值.原始文件每天每个名称包含24个数据(名称过多).例如,这里有一个名字的24个数据:

I have problem getting max value of each day from hourly data. Original file contain 24 data for each name each day(there are too many name). as example here is 24 data for one name:

Start Time  Period  name    value
2/23/2019 0:00  60  MBTS_H2145X 100
2/23/2019 1:00  60  MBTS_H2145X 100
2/23/2019 2:00  60  MBTS_H2145X 1
2/23/2019 3:00  60  MBTS_H2145X 1
2/23/2019 4:00  60  MBTS_H2145X 1
2/23/2019 5:00  60  MBTS_H2145X 2324
2/23/2019 6:00  60  MBTS_H2145X 2323
2/23/2019 7:00  60  MBTS_H2145X 2323
2/23/2019 8:00  60  MBTS_H2145X 2323
2/23/2019 9:00  60  MBTS_H2145X 2323
2/23/2019 10:00 60  MBTS_H2145X 2323
2/23/2019 11:00 60  MBTS_H2145X 2323
2/23/2019 12:00 60  MBTS_H2145X 1
2/23/2019 13:00 60  MBTS_H2145X 21
2/23/2019 14:00 60  MBTS_H2145X 21
2/23/2019 15:00 60  MBTS_H2145X 23
2/23/2019 16:00 60  MBTS_H2145X 350
2/23/2019 17:00 60  MBTS_H2145X 323
2/23/2019 18:00 60  MBTS_H2145X 23
2/23/2019 19:00 60  MBTS_H2145X 23
2/23/2019 20:00 60  MBTS_H2145X 2323
2/23/2019 21:00 60  MBTS_H2145X 23
2/23/2019 22:00 60  MBTS_H2145X 23
2/23/2019 23:00 60  MBTS_H2145X 2

我得到的结果是:(这是错误的,应该是2324)

the result I get is: (which is wrong and should be 2324)

    Start Time  name    max value
0   2/23/2019   MBTS_H2145X 350

我有以下代码,但结果不正确

I have below codes but I get wrong result

import dask.dataframe as dd
import numpy as np
import pandas as pd

filename='V.csv'
df = dd.read_csv(filename, dtype='str')


#_________changing date format 
df['Start Time'] = df['Start Time'].map(lambda x: pd.to_datetime(x, errors='coerce'))
#_________change to pure date without hour
df['Start Time'] = df['Start Time'].dt.date


grouped_df=(df.groupby(['Start Time','name']).agg({'value':'max'}).rename(columns={'value':'max value'}).reset_index())

grouped_df.to_csv('e1.csv')

print(grouped_df.head(12))

推荐答案

保持代码完全相同.只需将此行更改为:

Keep your code the exact same. Just Change this line to:

grouped_df=(df.groupby(['Start Time','name']).agg({'value':'max'}).rename(columns={'value':'max value'}).reset_index())

更改为:

df.value = pd.to_numeric(df.value)

grouped_df= (df.groupby(['Start Time','name'])['value'].max().rename(columns={'value':'max value'}).reset_index()

df = pd.merge(df, grouped_df, on  = ['Start Time','name'])

聚合函数可能会发生某些事情.

There might be something happening with the aggregate function.

或者如果您的DTYPE仅是STRING,则只需添加pd.to_numeric行,并保持其他所有内容不变.

OR IF YOUR DTYPE IS JUST STRING, then just add the pd.to_numeric line, and keep everything else the same.

这篇关于从每小时数据中找到每天的最大值的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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