删除冲销交易 [英] Remove reversal transaction
问题描述
我有一些冲销交易的交易水平数据.这些交易用负数表示,然后用正数表示.
I have transaction level data with some reversal transactions. These transactions are denoted by a negative amount and then a counterpart positive.
trnx_df <- data.frame(Date = c("2018-01-01", "2018-01-01", "2018-01-01", "2018-01-01", "2018-01-03", "2018-01-03", "2018-01-05", "2018-02-01",
"2018-02-01", "2018-02-01"),
Product = c("A", "A", "A", "A", "B", "B", "B", "A", "A", "A"),
Amount = c(-1000, 1000, 1000, 1000, -1000, 1000, 500, -2000, 1000, 2000))
trnx_df
Date Product Amount
1 2018-01-01 A -1000
2 2018-01-01 A 1000
3 2018-01-01 A 1000
4 2018-01-01 A 1000
5 2018-01-03 B -1000
6 2018-01-03 B 1000
7 2018-01-05 B 500
8 2018-02-01 A -2000
9 2018-02-01 A 1000
10 2018-02-01 A 2000
我想得出该客户在特定产品上花费的总金额和最高金额.
I want to arrive at total amount and maximum amount spent by that customer on particular product.
通过使用 dplyr 我到达:
library(dplyr)
trnx_summary <- trnx_df %>%
group_by(Product) %>%
summarize(Total_amount = sum(Amount),
Max_amount = max(Amount))
trnx_summary
Product Total_amount Max_amount
1 A 3000 2000
2 B 500 1000
总而言之,这是没有问题的,因为负数条目将抵消正数条目,但是如果花费最大,我将得到错误的输出结果.
For total there will be no problem as the negative entry will cancel out positive one but for maximum amount spent I will get wrong output.
产品A 的最大金额应为1000( 2000
和 -2000
将相互抵消).
The maximum amount for Product A should be 1000 (2000
and -2000
will cancel each other out).
我该如何解决?另外,是否有办法从 dataframe 本身删除这些冲销交易?
How can I fix this? Also, is there a way to delete these reversal transactions from the dataframe itself?
推荐答案
df %>% #filter the negative transactions, save in dftemp
filter(Amount < 0) %>%
mutate(Amount = abs(Amount)) -> dftemp # in dftemp, negative transactions are positive to ease looking for matches
df %>% #filter the positive transactions that do no have a negative duplicate
filter(Amount > 0) %>%
anti_join(dftemp) -> dfuniques
df %>%
filter(Amount > 0) %>% #filter positive transactions
inner_join(dftemp) %>% #merge obs that are both in the original df and in dftemp
group_by(Date, Product, Amount) %>% #group by date, product and amount
slice(-1) %>% #for each date, product & amount combo, delete 1 row (which is a duplicate of one negative and one positive transaction)
full_join(dfuniques) %>% # join the unique positive transactions (from here on, you have your desired dataframe with negative and positive transactions that cancelled each other out deleted)
group_by(Product) %>%
summarise(Total_Amount = sum(Amount), Max_Amount = max(Amount))
Product Total_Amount Max_Amount
<fctr> <dbl> <dbl>
1 A 3000 1000
2 B 500 500
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