R:求和，直到达到0，然后重新启动 [英] R: Sum until 0 is reached and then restart
问题描述
Adding on to what's already being said or commented on this post: Cumulative sum until maximum reached, then repeat from zero in the next row
我有一个类似的数据框，其中包含约50k多个观察值.正在从csv文件读取此数据帧，这是已经对其执行的若干操作的结果.在此处粘贴示例:
I've a similar dataframe which has about 50k+ observations. This dataframe was being read from a csv file and is an outcome of several operations already performed on it. Pasting a sample here:
Home Date Time Appliance Run value
679 2 1/21/2017 1:30:00 0 1 0
680 2 1/21/2017 1:45:00 0 1 0
681 2 1/21/2017 2:00:00 0 1 0
682 2 1/21/2017 2:15:00 0 1 0
683 2 1/21/2017 2:30:00 804 0 1
684 2 1/21/2017 2:45:00 556 0 804
685 2 1/21/2017 3:00:00 844 0 1360
686 2 1/21/2017 3:15:00 396 0 2204
687 2 1/21/2017 3:30:00 392 0 2600
688 2 1/21/2017 3:45:00 1220 0 2992
689 2 1/21/2017 4:00:00 0 1 0
690 2 1/21/2017 4:15:00 0 1 0
691 2 1/21/2017 4:30:00 0 1 0
692 2 1/21/2017 4:45:00 0 1 0
783 2 1/22/2017 3:30:00 0 1 0
784 2 1/22/2017 3:45:00 244 0 4212
785 2 1/22/2017 4:00:00 1068 0 4456
786 2 1/22/2017 4:15:00 44 0 5524
787 2 1/22/2017 4:30:00 1240 0 5568
788 2 1/22/2017 4:45:00 40 0 6808
789 2 1/22/2017 5:00:00 1608 0 6848
790 2 1/22/2017 5:15:00 0 1 0
791 2 1/22/2017 5:30:00 0 1 0
我使用的代码作为答案之一给出， df = transform(df，value = ave(Appliance，Run，FUN = function(x)c(1，head(cumsum(x)，-1)))).
The code I used, given as one of the answers, df = transform(df, value = ave(Appliance, Run, FUN = function(x)c(1, head(cumsum(x),-1)))).
但是，如您在输出中看到的，总和在下一次出现0时不会重新开始，并且第一组的最后总和(683-688索引)将结转到784(索引号).请帮助我在下次出现0时重新启动总和.
However, as you can see in the output, the sums won't restart at the next occurrence of 0 plus the last sum for first group (683-688 index) is carry forwarded to 784 (index number). Please help me in restarting the sums at next occurrence of 0.
预期输出:
Home Date Time Appliance Run value
679 2 1/21/2017 1:30:00 0 1 0
680 2 1/21/2017 1:45:00 0 1 0
681 2 1/21/2017 2:00:00 0 1 0
682 2 1/21/2017 2:15:00 0 1 0
683 2 1/21/2017 2:30:00 804 0 804
684 2 1/21/2017 2:45:00 556 0 1360
685 2 1/21/2017 3:00:00 844 0 2204
686 2 1/21/2017 3:15:00 396 0 2600
687 2 1/21/2017 3:30:00 392 0 2992
688 2 1/21/2017 3:45:00 1220 0 4212
689 2 1/21/2017 4:00:00 0 1 0
690 2 1/21/2017 4:15:00 0 1 0
691 2 1/21/2017 4:30:00 0 1 0
692 2 1/21/2017 4:45:00 0 1 0
783 2 1/22/2017 3:30:00 0 1 0
784 2 1/22/2017 3:45:00 244 0 244
785 2 1/22/2017 4:00:00 1068 0 1312
786 2 1/22/2017 4:15:00 44 0 1356
787 2 1/22/2017 4:30:00 1240 0 2596
788 2 1/22/2017 4:45:00 40 0 2636
789 2 1/22/2017 5:00:00 1608 0 4244
790 2 1/22/2017 5:15:00 0 1 0
791 2 1/22/2017 5:30:00 0 1 0
PS:我也已经尝试过:总和直到给定值达到
P.S: I've already tried this too: Sum until a given value is reached
推荐答案
这是一个 data.table 选项.您的分组变量不应为 Run ，而应为 rleid(Run).
Here is a data.table option. Your grouping variable should not be Run but rleid(Run).
library(data.table)
dt <- fread(text)
dt[, value := cumsum(Appliance), by = rleid(Run)]
dt
# V1 Home Date Time Appliance Run value
# 1: 679 2 1/21/2017 1:30:00 0 1 0
# 2: 680 2 1/21/2017 1:45:00 0 1 0
# 3: 681 2 1/21/2017 2:00:00 0 1 0
# 4: 682 2 1/21/2017 2:15:00 0 1 0
# 5: 683 2 1/21/2017 2:30:00 804 0 804
# 6: 684 2 1/21/2017 2:45:00 556 0 1360
# 7: 685 2 1/21/2017 3:00:00 844 0 2204
# 8: 686 2 1/21/2017 3:15:00 396 0 2600
# 9: 687 2 1/21/2017 3:30:00 392 0 2992
#10: 688 2 1/21/2017 3:45:00 1220 0 4212
#11: 689 2 1/21/2017 4:00:00 0 1 0
#12: 690 2 1/21/2017 4:15:00 0 1 0
#13: 691 2 1/21/2017 4:30:00 0 1 0
#14: 692 2 1/21/2017 4:45:00 0 1 0
#15: 783 2 1/22/2017 3:30:00 0 1 0
#16: 784 2 1/22/2017 3:45:00 244 0 244
#17: 785 2 1/22/2017 4:00:00 1068 0 1312
#18: 786 2 1/22/2017 4:15:00 44 0 1356
#19: 787 2 1/22/2017 4:30:00 1240 0 2596
#20: 788 2 1/22/2017 4:45:00 40 0 2636
#21: 789 2 1/22/2017 5:00:00 1608 0 4244
#22: 790 2 1/22/2017 5:15:00 0 1 0
#23: 791 2 1/22/2017 5:30:00 0 1 0
#24: 792 2 1/22/2017 5:45:00 0 1 0
#25: 793 2 1/22/2017 6:00:00 0 1 0
#26: 794 2 1/22/2017 6:15:00 0 1 0
#27: 795 2 1/22/2017 6:30:00 0 1 0
#28: 796 2 1/22/2017 6:45:00 0 1 0
#29: 797 2 1/22/2017 7:00:00 0 1 0
#30: 798 2 1/22/2017 7:15:00 0 1 0
在 base R 中我们可以做到
df1 <- read.table(text = text, stringsAsFactors = FALSE, header = TRUE)
rle_Run <- rle(df1$Run)
df1$value <- with(df1, ave(Appliance, rep(seq_along(rle_Run$lengths), rle_Run$lengths), FUN = cumsum))
数据
text <- " Home Date Time Appliance Run value
679 2 1/21/2017 1:30:00 0 1 0
680 2 1/21/2017 1:45:00 0 1 0
681 2 1/21/2017 2:00:00 0 1 0
682 2 1/21/2017 2:15:00 0 1 0
683 2 1/21/2017 2:30:00 804 0 1
684 2 1/21/2017 2:45:00 556 0 804
685 2 1/21/2017 3:00:00 844 0 1360
686 2 1/21/2017 3:15:00 396 0 2204
687 2 1/21/2017 3:30:00 392 0 2600
688 2 1/21/2017 3:45:00 1220 0 2992
689 2 1/21/2017 4:00:00 0 1 0
690 2 1/21/2017 4:15:00 0 1 0
691 2 1/21/2017 4:30:00 0 1 0
692 2 1/21/2017 4:45:00 0 1 0
783 2 1/22/2017 3:30:00 0 1 0
784 2 1/22/2017 3:45:00 244 0 4212
785 2 1/22/2017 4:00:00 1068 0 4456
786 2 1/22/2017 4:15:00 44 0 5524
787 2 1/22/2017 4:30:00 1240 0 5568
788 2 1/22/2017 4:45:00 40 0 6808
789 2 1/22/2017 5:00:00 1608 0 6848
790 2 1/22/2017 5:15:00 0 1 0
791 2 1/22/2017 5:30:00 0 1 0
792 2 1/22/2017 5:45:00 0 1 0
793 2 1/22/2017 6:00:00 0 1 0
794 2 1/22/2017 6:15:00 0 1 0
795 2 1/22/2017 6:30:00 0 1 0
796 2 1/22/2017 6:45:00 0 1 0
797 2 1/22/2017 7:00:00 0 1 0
798 2 1/22/2017 7:15:00 0 1 0"
这篇关于R:求和，直到达到0，然后重新启动的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
