如何根据列组的平均值对数据框进行重新排序 [英] How to reorder a data frame based on mean of column groups

问题描述

我正在尝试根据与列ID关联的中位数对数据帧进行重新排序.

I am trying to reorder a data frame based on the median value associated with a column ID.

我有一个带有一列ID和两列值的数据框.

I have a dataframe with a column of IDs and 2 columns of values.

ID <- c("a","a","a","b","b","b","c","c","c","c")
alpha <- c(3,4,5,9,11,13,1,1,1,0)
beta <- c(2,3,4,3,4,5,4,5,6,7)
df <- data.frame(ID,alpha,beta)

   ID alpha beta
1   a     3    2
2   a     4    3
3   a     5    4
4   b     9    3
5   b    11    4
6   b    13    5
7   c     1    4
8   c     1    5
9   c     1    6
10  c     0    7

我想对该数据帧重新排序，以使列ID的顺序基于alpha列中相关值的递减方式:

I want to reorder this dataframe so that the column ID is in an order based on the decending means of the associated values in the alpha column:

   ID alpha beta
1   b     9    3
2   b    11    4
3   b    13    5
4   a     3    2
5   a     4    3
6   a     5    4
7   c     1    4
8   c     1    5
9   c     1    6
10  c     0    7

这不成功:

df[reorder(df$ID, df$alpha, FUN = mean),]

推荐答案

尝试

library(dplyr)
df %>% group_by(ID) %>% mutate(m = mean(alpha)) %>% arrange(desc(m)) %>% select(-m)
# A tibble: 10 x 3
# Groups:   ID [3]
       ID alpha  beta
   <fctr> <dbl> <dbl>
 1      b     9     3
 2      b    11     4
 3      b    13     5
 4      a     3     2
 5      a     4     3
 6      a     5     4
 7      c     1     4
 8      c     1     5
 9      c     1     6
10      c     0     7

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