更改AutoGeneratingColumn中的DataGrid列显示值 [英] Change DataGrid Column display value in AutoGeneratingColumn

问题描述

我有 dataGrid.ItemsSource 绑定到EntityItem列表 Client ，其中包含另一个EntityItem Company .

I have dataGrid.ItemsSource bound to a list of EntityItem, Client, that containt another EntityItem, Company.

当显示我的 dataGrid 时，在我的 Company 列中，我具有对象的类型( System.Data.Entity....)我想显示我的 Company.Name .

When my dataGrid is displayed, in my Company Column, I have the type of my object (System.Data.Entity. ...) I would like instead to display my Company.Name.

在WindowsForm中，我可以这样做:

In WindowsForm I could just do :

e.Value = ((Company)(dgv["Company", e.RowIndex].Value)).Name;

但是我找不到在WPF中正确执行操作的方法.

But I can't find a way to do in properly in WPF.

现在我有:

private void dataGridUsers_AutoGeneratingColumn_1(object sender, DataGridAutoGeneratingColumnEventArgs e)
    {

        DataGrid dgv = (DataGrid)sender;
        if (e.PropertyName == "Company")
        { 
            if (e.PropertyType == typeof(Company))
            {
                ...
            }
        }
    }

所以我可以确保我在正确的列上，但是现在我被卡住了，我不知道如何更改我希望该列显示数据的方式...我尝试查看 e.PropertyDescriptor ，但这仅是为了获取属性.

So I can make sure I'm on the right column, but now I'm stuck, I don't know how to change the way I want the column to display the data ... I tried to look into e.PropertyDescriptor but it's only to Get the properties.

推荐答案

DataGridAutoGeneratingColumnEventArgs 对象具有 Column 属性，该属性包含一个生成的 DataGridColumn 实例.具体类型为 DataGridTextColumn ，它具有 Binding 属性.

DataGridAutoGeneratingColumnEventArgs object has Column property which contains a generated DataGridColumn instance. Concrete type is DataGridTextColumn, which has Binding property.

您可以更改绑定路径以使用 Column.Name 属性

You can change binding path to work with Column.Name property

private void DataGridOnAutoGeneratingColumn(object sender, DataGridAutoGeneratingColumnEventArgs e)
{
    if (e.PropertyName == "Company")
    {
        var c = (DataGridTextColumn)e.Column;
        var b = (Binding)c.Binding;
        b.Path = new PropertyPath("Company.Name");
    }
}

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