有没有一种方法可以基于列中的因数来遍历数据并累加行数? [英] Is there a way to loop through data based on factor in a column and add up the number of rows?

问题描述

我有一些数据，可以对同一事件进行多次观察.基于时间阈值，我想浓缩一下观察结果.但是我想知道我正在凝结多少个(即，有多少个观察成为一个观察).我不确定如何以这种方式遍历数据框.

I have some data in which I have multiple observations of the same event. Based on a threshold of time, I want to condense the observations. But I want to know how many I am condensing (i.e. how many observations become one). I'm not sure how to loop through my dataframe in such a way to do that.

我尝试编写for循环，if语句，while语句，并在google和堆栈溢出上进行了不懈的搜索.似乎与我需要做的事情无关.

I've tried writing a for loop, if statements, while statements, and have searched tirelessly on google and on stack overflow. Nothing seems to relate to what I need to do.

这是我的数据的子集:

structure(list(date.time = structure(c(1465877617, 1465877774, 
1465877816, 1465877844, 1465912214, 1465912806, 1465912862, 1465914033
), class = c("POSIXct", "POSIXt"), tzone = "America/New_York"), 
    time = structure(1:8, .Label = c("00:13:37", "00:16:14", 
    "00:16:56", "00:17:24", "09:50:14", "10:00:06", "10:01:02", 
    "10:20:33"), class = "factor"), X = c(1, 1, 1, 1, 1, 1, 1, 
    1), diff_time1 = structure(c(157, 42, 28, 34370, 592, 56, 
    1171, 2820), class = "difftime", units = "secs"), diff_time2 = c(FALSE, 
    FALSE, FALSE, TRUE, FALSE, FALSE, TRUE, TRUE), new = c("start", 
    "include", "include", "end", "start", "include", "end", "start-end"
    )), row.names = c(NA, 8L), class = "data.frame")

目标是使它看起来像下面，但是为每个被污染"的观察结果增加一列样本大小:

The goal is to get it to look like below, but with an additional column of sample size for each "smushed" observation:

structure(list(n = 1:8, end = structure(c(1465877844, 1465912862, 
1465914033, 1465916853, 1465921999, 1465928992, 1465933159, 1465937668
), class = c("POSIXct", "POSIXt")), start = structure(c(1465877617, 
1465912214, 1465914033, 1465916853, 1465921999, 1465928647, 1465932867, 
1465937418), class = c("POSIXct", "POSIXt")), date = structure(c(16966, 
16966, 16966, 16966, 16966, 16966, 16966, 16966), class = "Date")), row.names = c(NA, 
-8L), class = c("tbl_df", "tbl", "data.frame"))

推荐答案

library(dplyr); library(lubridate)
df %>%
  mutate(time_since_last = (date.time - lag(date.time, default = first(date.time))) / dminutes(1)) %>%
  mutate(group = 1 + cumsum(time_since_last > 15)) %>% # How many times was there a 15min+ gap? Each new one increments "group"
  group_by(group) %>%
  summarize(first = min(date.time), # or first(date.time) if sorted
            last  = max(date.time), # or last(date.time) if sorted
            count = n())

## A tibble: 3 x 4
#  group first               last                count
#  <dbl> <dttm>              <dttm>              <int>
#1     1 2016-06-14 00:13:37 2016-06-14 00:17:24     4
#2     2 2016-06-14 09:50:14 2016-06-14 10:01:02     3
#3     3 2016-06-14 10:20:33 2016-06-14 10:20:33     1

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