bigquery每日汇总 [英] bigquery aggregate for daily basis
问题描述
我在big-query(数据仓库)中有一个表:
I have a table in big-query (datawarehouse):
,我希望得到以下结果:
and I would like to have the result of:
以下是有关计算方式的说明:
Here is the explanation on how the calculation should be:
- 2017-10-01 = $ 100很明显,因为数据只是一个
- 2017-10-02 = $ 400是第一行和第三行的总和.为什么?因为第二行和第三行具有相同的发票.因此,我们仅使用最新更新.
- 2017-10-04 = $ 800是第1,3和4行的总和.为什么?这是因为我们每天只收一张发票.第1行(T001),第3行(T002),第4行(T003)
- 2017-10-05 = $ 100是行1,5和6的总和.为什么?这是因为我们每天仅收取一张发票.第1行(T001),第5行(T002),第6行(T003)
老实说,我已经完全不知道该怎么做.我已经尝试过多次按等分组,但是它们都没有按预期方式工作.这是我到目前为止所做的最新努力:
I honestly have completely lost how to do that. I have tried multiple times to group by and etc. But none of them work as expected. This is my latest effort so far for today:
SELECT
amount,
updatedDateOnly,
invNo
FROM
(
SELECT
invNo,
UpdatedDate,
amount,
DATE(updatedDate) as updatedDateOnly,
row_number() OVER (PARTITION BY invNo ORDER BY UpdatedDate DESC) AS rownum
FROM [project:dataset.test]
)
WHERE
rownum = 1
仅返回最后一个日期.现在,我不知道如何每天查询.
only returns the last date. Now, I have no idea how to query for daily basis.
感谢任何有专业知识并愿意帮助查询的人.谢谢.
Appreciate for anyone who is expert and willing to help in querying. Thank you.
更新:json中的数据,以防您想在bigquery或其他SQL服务器中尝试使用
UPDATE: Data in json, in case you want to try in bigquery or other SQL servers:
{"UpdatedDate":"2017-10-01 01:00:00","InvNo":"T001","amount":100}
{"UpdatedDate":"2017-10-02 01:00:00","InvNo":"T002","amount":200}
{"UpdatedDate":"2017-10-02 02:00:00","InvNo":"T002","amount":300}
{"UpdatedDate":"2017-10-04 01:00:00","InvNo":"T003","amount":400}
{"UpdatedDate":"2017-10-05 01:00:00","InvNo":"T002","amount":500}
{"UpdatedDate":"2017-10-05 02:00:00","InvNo":"T003","amount":500}
推荐答案
以下是BigQuery标准SQL
Below is for BigQuery Standard SQL
#standardSQL
WITH dates AS (
SELECT DISTINCT DATE(UpdatedDate) UpdatedDay
FROM `project.dataset.test`
),
qualified AS (
SELECT DATE(UpdatedDate) UpdatedDay, InvNo, ARRAY_AGG(amount ORDER BY UpdatedDate DESC LIMIT 1)[SAFE_OFFSET(0)] amount
FROM `project.dataset.test`
GROUP BY UpdatedDay, InvNo
)
SELECT UpdatedDay, SUM(amount) amount
FROM (
SELECT d.UpdatedDay UpdatedDay, InvNo, ARRAY_AGG(amount ORDER BY q.UpdatedDay DESC LIMIT 1)[SAFE_OFFSET(0)] amount
FROM dates d
JOIN qualified q
ON q.UpdatedDay <= d.UpdatedDay
GROUP BY UpdatedDay, InvNo
)
GROUP BY UpdatedDay
-- ORDER BY UpdatedDay
您可以使用问题中的以下虚拟数据进行测试/操作
You can test / play with this with below dummy data from your question
#standardSQL
WITH `project.dataset.test` AS (
SELECT TIMESTAMP '2017-10-01 01:00:00' UpdatedDate, 'T001' InvNo, 100 amount UNION ALL
SELECT TIMESTAMP '2017-10-02 01:00:00', 'T002', 200 UNION ALL
SELECT TIMESTAMP '2017-10-02 02:00:00', 'T002', 300 UNION ALL
SELECT TIMESTAMP '2017-10-04 01:00:00', 'T003', 400 UNION ALL
SELECT TIMESTAMP '2017-10-05 01:00:00', 'T002', 500 UNION ALL
SELECT TIMESTAMP '2017-10-05 02:00:00', 'T003', 500
),
dates AS (
SELECT DISTINCT DATE(UpdatedDate) UpdatedDay
FROM `project.dataset.test`
),
qualified AS (
SELECT DATE(UpdatedDate) UpdatedDay, InvNo, ARRAY_AGG(amount ORDER BY UpdatedDate DESC LIMIT 1)[SAFE_OFFSET(0)] amount
FROM `project.dataset.test`
GROUP BY UpdatedDay, InvNo
)
SELECT UpdatedDay, SUM(amount) amount
FROM (
SELECT d.UpdatedDay UpdatedDay, InvNo, ARRAY_AGG(amount ORDER BY q.UpdatedDay DESC LIMIT 1)[SAFE_OFFSET(0)] amount
FROM dates d
JOIN qualified q
ON q.UpdatedDay <= d.UpdatedDay
GROUP BY UpdatedDay, InvNo
)
GROUP BY UpdatedDay
ORDER BY UpdatedDay
结果符合预期
UpdatedDay amount
2017-10-01 100
2017-10-02 400
2017-10-04 800
2017-10-05 1100
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