使用seq()创建规则的日期时间序列(POSIXct) [英] Create a regular sequence of date-times (POSIXct) using seq()

查看:88
本文介绍了使用seq()创建规则的日期时间序列(POSIXct)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我的目标是创建一个给定起点,终点和增量(15分钟,1小时,1天)的POSIXct时间戳向量.我希望可以为此使用 seq ,但是在数字和POSIXct表示之间进行转换时遇到问题:

My goal is to create a vector of POSIXct time stamps given a start, an end and a delta (15min, 1hour, 1day). I hoped I could use seq for this, but I have a problem converting between the numeric and POSIXct representation:

now <- Sys.time()
now
# [1] "2012-01-19 10:30:39 CET"
as.POSIXct(as.double(now), origin="1970-01-01", tz="CET")
# [1] "2012-01-19 09:30:39 CET"
as.POSIXct(as.double(now), origin=as.POSIXct("1970-01-01", tz="CET"), tz="CET")
# [1] "2012-01-19 09:30:39 CET"

此转换过程中浪费了一个小时.我在做什么错了?

One hour gets lost during this conversion. What am I doing wrong?

推荐答案

对于超类为"POSIXt" 的对象,有一个 seq()方法"POSIXlt" "POSIXct" 类的集合.因此,您无需进行任何转换.

There is a seq() method for objects of class "POSIXt" which is the super class of the "POSIXlt" and "POSIXct" classes. As such you don't need to do any conversion.

> now <- Sys.time()
> tseq <- seq(from = now, length.out = 100, by = "mins")
> length(tseq)
[1] 100
> head(tseq)
[1] "2012-01-19 10:52:38 GMT" "2012-01-19 10:53:38 GMT"
[3] "2012-01-19 10:54:38 GMT" "2012-01-19 10:55:38 GMT"
[5] "2012-01-19 10:56:38 GMT" "2012-01-19 10:57:38 GMT"

这篇关于使用seq()创建规则的日期时间序列(POSIXct)的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆