将日期从UTC转换为CET [英] Converting date from UTC to CET

问题描述

我想将以 UTC 格式给出的日期转换为以 CET 格式给出的日期.

I would like to convert a date given in the UTC format to a date in the CET format.

问题是我需要相应地增加或减少小时数.

The problem is that I need to add or subtract hours accordingly.

示例:

Date = "2015-07-31 01:14:05"

我想将其转换为德语日期(加两个小时):

I would like to convert it to German date (adding two hours):

2015-07-31 03:14:05" 

我的代码:

private static Long convertDateFromUtcToCet(String publicationDate) {
    //"2015-07-31 01:14:05"

    SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-mm-dd hh:mm:ss");
    //SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-mm-dd");
    Date date = null;
    try {
        date = simpleDateFormat.parse(publicationDate);
    } catch (ParseException e) {
        e.printStackTrace();
    }
    Calendar calendar = Calendar.getInstance(TimeZone.getTimeZone("UTC"));
    calendar.setTime(date);
    Date givenDate = calendar.getTime();
    System.out.println("Original UTC date is: " + givenDate.toString());

    TimeZone timeZone = TimeZone.getTimeZone("CET");
    calendar.setTimeZone(timeZone);
    Date currentDate = calendar.getTime();
    System.out.println("CET date is: " + currentDate.toString());

    long milliseconds = calendar.getTimeInMillis();

    return milliseconds;
}

此打印:

Original UTC date is: Sat Jan 31 01:14:05 IST 2015
CET date is: Sat Jan 31 01:14:05 IST 2015

推荐答案

首先，您的模式字符串错误.是 yyyy-MM-dd ，而不是 yyyy-mm-dd .

First of all, your pattern string is wrong. It's yyyy-MM-dd, not yyyy-mm-dd.

SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss");

要解析给定的时区，请设置为:

To parse with a given time zone, set it with:

simpleDateFormat.setTimeZone(TimeZone.getTimeZone("UTC"));

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