ISO8601格式的字符串转换为DateTime [英] ISO8601 formatted string to DateTime
本文介绍了ISO8601格式的字符串转换为DateTime的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我具有以下ISO8601格式的日期时间字符串:
I have the following ISO8601 formatted date time string:
2016-03-28T16:07:00 + 0200
我想将其转换为C# DateTime
对象,但是我使用的解析方法会引发异常.
I want to convert it into a C# DateTime
object, but the parsing method I'm using throws an exception.
当前,我有这个:(不起作用)
string format = "yyyy-MM-ddTHH:mm:ss+zzzz";
CultureInfo provider = CultureInfo.InvariantCulture;
// Throws the exception: "String was not recognized as a valid DateTime."
DateTime time = DateTime.ParseExact("2016-03-28T16:07:00+0200", format, provider);
如何使解析函数与我的字符串配合使用?
How do I get the parse function to work with my string?
推荐答案
尝试 DateTime时间= DateTime.Parse("2016-03-28T16:07:00 + 0200");
.您的字符串似乎是
Try DateTime time = DateTime.Parse("2016-03-28T16:07:00+0200");
. Your string seems to be a format that will be recognized by DateTime.Parse()
.
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