减去两个DateTime对象-Python [英] Subtract Two DateTime objects - Python

问题描述

我有两个这样的日期时间对象

I have two date time objects like this

a = first date time object
b = second date time object

然后

c = a - b

现在，我想比较c并检查时差是否大于3小时，所以我有一个名为 three_hours

Now I want to compare c and check if the difference was greater than 3 hours, so I have a time object called three_hours

three_hours = datetime.time(3,0)
if c >= three_hours:
     #do stuff

但是我收到一条错误消息，说无法将datetime.teimdelta与datetime.time进行比较

but I get an error saying cannot compare datetime.teimdelta to datetime.time

我的问题有所不同，因为我也想比较减去的时间，而不仅仅是得到差异！

My question is different as I also want to then compare the subtracted time, not just get the difference!!

如何将它们转换为正确的格式，以便检查是否已过去3个小时?

How can I convert them to the correct formats so I can check if 3 hours has passed?

感谢您的帮助

推荐答案

在python中减去两个datetime对象时，您会得到一个

When you subtract two datetime objects in python, you get a datetime.timedelta object. You can then get the total_seconds() for that timedelta object and check if that is greater than 3*3600 , which is the number of seconds for 3 hours. Example -

>>> a = datetime.datetime.now()
>>> b = datetime.datetime(2015,8,25,0,0,0,0)
>>> c = a - b
>>> c.total_seconds()
87062.729491
>>> c.total_seconds() > 3*3600
True

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