如何创建一个可以将多个装饰器应用于另一个函数的函数? [英] How to create a function that can apply multiple decorators to another function?

问题描述

假设我有一个由多个装饰器装饰的函数.

Let's say I have a function that is decorated by multiple decorators.

# file.py

@deco1
@deco2('param')
@deco3(
    'multiple',
    'long',
    'params'
)
@deco4('multiple', 'params')
def foo():
    """Function foo
    """
    pass

让我们说它看起来很脏.很脏.

Let's just say it looks very dirty. VERY dirty.

我希望能够做这样的事情.

I want to be able to do something like this.

# another_file.py

@deco1
@deco2('param')
@deco3(
    'multiple',
    'long',
    'params'
)
@deco4('multiple', 'params')
def all_decorators_for_foo():
    ...

# file.py

from another_file import all_decorators_for_foo

@all_decorators_for_foo
def foo():
    """Yay!
    """
    ...

仅出于上下文考虑，多个装饰器是sanic框架的草率文档装饰器.

Just for the sake of context, the multiple decorators are swagger documentation decorators for sanic framework.

在python中是否有可能实现类似的目的?

Is it possible in python to achieve something similar to this?

此问题不能以任何方式回答我的问题问题.装饰器无论如何都可以堆叠在一起并使用.我想要一种可以代替所有堆叠式装饰器的装饰器.

This question does not in any way answer my question. Decorators can anyway be stacked together and used. I want some sort of decorator that can be used in place of all the stacked decorators.

推荐答案

可以.您可以使另一个装饰器返回装饰后的函数，如下所示:
all_decorators_for_foo.py

Yes you could. You can make another decorator that returns the decorated function like so:
all_decorators_for_foo.py

def all_decorators_for_foo(func):
    return deco1()(
        deco2('param')(
            deco3(
                'multiple',
                'long',
                'params'
            )(
                deco4('multiple', 'params')(
                    func
                )
            )
        )
    )

，然后在 file.py

from another_file import all_decorators_for_foo

@all_decorators_for_foo
def foo():
    pass

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