如何使用自定义网址方案启动android应用 [英] how to launch an android app with custom url scheme

问题描述

我想从自定义URL方案启动我的应用程序.我检查了开发android上的深层链接"部分，这是我的代码段.不过，使用似乎如下的URL似乎不会触发:myApp://?host = myhost.com

I want to launch my app from a custom URL scheme. I checked the deep links section on dev android and here is a snippet of my code. This doesnt seem to fire though with a URL that looks like : myApp://?host=myhost.com

清单:

<intent-filter>
    <action android:name="android.intent.action.MAIN" />

    <category android:name="android.intent.category.LAUNCHER" />
    <category android:name="android.intent.category.BROWSABLE" />

    <data android:scheme="myApp" />
</intent-filter>

在我主要的活动中，我有:

In the activity which is my main activity, i have :

Intent intent = getIntent();
Uri uri = intent.getData();
if (uri != null) {
    String host = uri.getQueryParameter("host");
}

当我有以URL作为超链接的电子邮件时，该应用程序无法启动.另外，什么是测试此内容的好方法?

The app does not launch when i have email that has the url as a hyperlink. Also, what would be a good way to test this ?

推荐答案

浏览器将方案转换为小写，因此您需要将数据标签更改为

The browser converts the scheme to lowercase, so you need to change the data tag to

<data android:scheme="myapp"/>

这篇关于如何使用自定义网址方案启动android应用的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！