延迟启动流程 [英] start processes with a delay

问题描述

如何启动5个不同的进程，每个进程都有各自的延迟，而又不等待其他进程等待延迟完成?我不能使用异步或等待

How can I start 5 different processes, each with their own delay without holding up the other ones while waiting for the delay to finish? I can not use async or await

 foreach(string process1 in _processList)
  {
     // random delay
     Process.Start(process1);
    }

推荐答案

您可以从不同的线程启动每个进程.

You could start every process from a different thread.

foreach (string process1 in _processList)
{
  Thread t = new Thread(() => 
           {
               Thread.Sleep(/*RANDOM NUMBER*/ 5);
               Process.Start(process1);
           });
  t.Start();
}

这样，每个进程在启动之前都会有一个随机计时器，并且不会因为另一个进程的启动而延迟任何进程.

That way each process will have a random timer before it start and no process is delayed for the start of an other process.

如果在您的情况下完全不可能启动线程，我建议将您的进程包装到.bat中，并在此批处理文件中添加睡眠延迟，这样将及时调用所有进程，并且将遵守睡眠延迟

If starting thread is totaly impossible in your situation, i would suggest wrapping your process to a .bat and in this batch file you add the sleep delay this way all the process will be called in time and the sleep delay will be respected.

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