数组解构跳过值 [英] Array Destructuring Skipping Values

问题描述

我的 airbnb样式指南告诉我，对于

const splittedArr  = [1, 2, 3, 4, 5]
const result = splittedArr[1];

所以我这样写，使用跳过值 来获取第二个元素.

So I wrote it like this using skipping values , to get the second element.

const splittedArr  = [1, 2, 3, 4, 5]
const [, result] = splittedArr;

const splittedArr = [1, 2, 3, 4, 5]
const result = splittedArr[1];

const [, res] = splittedArr;

console.log(result, res);

但是例如当我有更高的指数要破坏时

But for instance when I have a higher indice to destruct

const splittedArr  = [1, 2, 3, 4, 5]
const result = splittedArr[5];

这意味着我必须像这样写

This would mean I have to write it like

const splittedArr  = [1, 2, 3, 4, 5]
const [,,,, result] = splittedArr;

const splittedArr  = [1, 2, 3, 4, 5]

const result = splittedArr[4];

const [, , , , res] = splittedArr;

console.log(result, res);

问题:是否有更好的方法用JavaScript中的跳过值来编写数组解构?

Question: Is there a better way to write Array Destructuring with skipping values in JavaScript?

推荐答案

您可以将数组视为对象，并使用索引作为键和

You could treat the array as object and destructure with the index as key and assign to a new variable name.

const
    array = [37, 38, 39, 40, 41, 42, 43],
    { 5: result } = array;

console.log(result);

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