将列表转换成字典 [英] Convert list into a dictionary

问题描述

l = ["a", "b", "c", "d", "e"]

我想将此列表转换为字典，例如:

I want to convert this list to a dictionary like:

d = {"a": "b", "c": "d", "e": ""}

因此，基本上，偶数将是关键，而几率将是值.我知道我可以通过非Python"方式(例如使用if语句的for循环)来完成此操作，但我相信应该有一种更"pythonic"的方式来完成此操作.因此，感谢您的帮助:)

So basically, the evens will be keys whereas the odds will be values. I know that I can do it in a "non-pythonic" way such as a for loop with if statements but I believe that there should be a more "pythonic" way to accomplish this. So, I appreciate any help :)

推荐答案

使用常规的石斑鱼食谱，您可以这样做:

Using the usual grouper recipe, you could do:

Python 2:

d = dict(itertools.izip_longest(*[iter(l)] * 2, fillvalue=""))

Python 3:

d = dict(itertools.zip_longest(*[iter(l)] * 2, fillvalue=""))

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