在Python中操作字典 [英] Manipulating dictionaries in Python

问题描述

我有一本可以存储月份的字典:

  Months = {'一月':1，'二月':2，'三月':3，'四月':4，'五月':5，'六月':6，6，七月':7，八月":8，九月":9，十月":10，十一月":11，十二月":12 

我有一个while循环，它循环12次(一年):

(伪)

  Month = 1决赛= 12而月份< =最终:在此处致电Month_from_dictionary_as_string_here月+ = 1 

如何根据另一个变量的值调用字典键?谢谢.

解决方案

我的意思是使用 while 循环( while 循环很少用于python中的迭代)，那么您需要为此目的使用反向哈希或字典

  reverse_months = {value:键的键，Months.items()中的值}print(reverse_months [1])#一月 

更好的实现方式是使用 for 循环-

 在范围(1，13)中的月份:打印(reverse_months [month]) 

尽管，为什么首先需要使用 looping ，但我想您可以轻松地使用迭代器，除非您的用例与您的代码所建议的有很大不同.

密钥的

 ，在Months.items()中的值:print(键:{0}，值:{1}".格式(键，值) 

P.S.-对于python中的命名约定，也请通过 Pep 8准则>

I have a dictionary that stores months:

Months = {'January': 1, 'February': 2, 'March': 3, 'April': 4, 'May': 5, 'June': 6, 'July': 7, 'August': 8, 'September': 9, 'October': 10, 'November': 11, 'December': 12

And I have a while loop, that loops 12 times (one year):

(pseudo)

Month = 1
Final = 12
while Month <= Final:
    call Month_from_dictionary_as_string_here
    Month += 1

how can I call dictionary keys depending on the value of the other variable? Thanks.

解决方案

I you are meant on using while loop(while loop is seldom used for iteration in python), then you need a reverse hash or dictionary for this purpose

reverse_months = {value: key for key, value in Months.items()}

print(reverse_months[1]) # January

A better implementation would be using for loop -

for month in range(1, 13):
    print(reverse_months[month])

Although, why do you need looping at all in first place, I guess you can easily make do with an iterator, unless your use case is much different from what your code suggests.

for key, value in Months.items():
    print("key: {0}, value: {1}".format(key, value)

P.S. - Please go through Pep 8 guidelines too for naming conventions in python

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