在python上获取字典的前x个元素 [英] take the first x elements of a dictionary on python

问题描述

我是python的新手，所以我尝试使用python字典的前50个元素.我有一本按值递减的字典.

I am a newbie on python, so I try to take the first 50 elements of a dictionary in python. I have a dictionary which is decreasing order sorted by value.

k=0
l=0
for k in len(dict_d):
    l+=1
    if l<51:
        print dict

举个小例子:

 dict_d={'m':'3','k':'4','g':'7','d':'9'}

获取新词典中的前3个元素:

take the first 3 elements in a new dictionary:

 new_dict={'m':'3','k':'4','g':'7'}

我找不到该怎么做?

推荐答案

dict_d = {...}
for key in sorted(dict_d)[:50]:
    print key, dict_d[key]

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