从函数迭代字典 [英] iterate dictionary from a function

问题描述

从函数迭代字典时遇到问题.

I'm having a problem iterating dictionary from a function.

def iteratedic():
    datadic={
    "one" : 1,
    "two" : 2,
    "three" : 3,
    "four" : 4
    }

    return datadic

def getdic():
    dictionary = iteratedic()
    for m, n in dictionary:
        print (m, n)

getdic()

说

ValueError:太多值无法解包(预期2)

ValueError: too many values to unpack (expected 2)

推荐答案

您必须遍历 .items():

def iteratedic():
    datadic={
    "one" : 1,
    "two" : 2,
    "three" : 3,
    "four" : 4
    }

    return datadic

def getdic():
    dictionary = iteratedic()
    for m, n in dictionary.items():
        print (m, n)

getdic()

如果打印 dictionary ，您会看到得到 {'four':4，4，'three':3，'two':2，'one':1} .如果打印 dictionary.items()，您将获得项目列表. [(''four'，4)，('three'，3)，('two'，2)，('one'，1)] .

If you print dictionary you'll see that you get {'four': 4, 'three': 3, 'two': 2, 'one': 1} . If you print dictionary.items() you get the list of the items. [('four', 4), ('three', 3), ('two', 2), ('one', 1)].

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