如何获取与同一词典中的另一个键共享值的键列表? [英] How to get list of keys that share a value with another key within the same dictionary?

问题描述

我有一个唯一键字典，其中某些键共享相同的值.

I have a dictionary of unique keys where some keys share the same value.

例如:

D = {'ida':{'key':'1'},'idb':{'key':'2'},'idc':{'key':'3'},'idd':{'key':'3'},'ide':{'key':'4'},'idf':{'key':'4'},'idg':{'key':'4'}}

我想要一个与其他键共享相同值的键列表.

I want a list of keys that share the same value with other keys.

在这种情况下，应该是

l = ['idc','idd','ide','idf','idg']

但是，我想从共享相同值的所有键集中排除一个键.

However, I want to exclude one key from all sets of keys that share the same value.

例如，我想要按键

l = ['idd','idf','idg']

其中不包括"idc"和"ide"

which excludes 'idc' and 'ide'

或者可能是

l = ['idc','ide','idf']

，其中不包括"idd"和"idg".

which excludes 'idd' and 'idg'.

推荐答案

如果该值多次出现，列表组合将添加键.

If the value appears more than once the list comp will add the key.

dup_keys = [k for k in D if sum(D[k] in x for x in D.iteritems()) > 1 ]

['idf', 'idg', 'idd', 'ide', 'idc']

dup_keys[1:]
['idg', 'idd', 'ide', 'idc']
dup_keys[1:-1]
['idg', 'idd', 'ide']

如果sum(D.k中的D [k]等于D.iteritems()中的x)，1 检查值是否出现>1 次.

要忽略某些键，请添加一些和条件，但我不确定要在什么基础上忽略键.

To ignore certain keys add some and condition, I am not sure on what basis you want to ignore the keys.

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