仅在左侧或右侧比较对象 [英] compare-object left or right side only

问题描述

快速提问

是否有更好的方法(例如，效率更高/更简洁)?

Is there a better (i.e. more efficient / more concise) way to do this?

compare-object $a $b | ?{$_.SideIndicator -eq '<='}

详细信息

比较对象为参数提供 -excludeDifferent 和 -includeEqual 参数，以允许您修改获得的结果.

Compare-Object gives paramenters -excludeDifferent and -includeEqual to allow you to amend which results you get.

• 同时使用这两种方法可以使您获得内部连接
• 仅使用 -includeEqual 即可为您提供完整的外部联接
• 仅使用 -excludeDifferent 是没有意义的；因为默认情况下，相等项被排除在外，所以现在它将排除所有内容.

• using both gives you an inner join
• using just -includeEqual gives you a full outer join
• using just -excludeDifferent is pointless; as by default equal items are excluded, so it will now exclude everything.

没有 -includeLeft ， -excludeLeft 或类似选项的选项.

There are no options for -includeLeft, -excludeLeft or similar.

当前要做的是左侧为null的外部外部联接(即参考对象中不在差异对象中的项目)，我需要按照上面的代码手动过滤结果.

Currently to do a left outer join where the right side is null (i.e. items in the reference object which are not in the difference object) I need to filter the results manually, as per the code above.

我错过了什么吗/有更好的方法吗?

Have I missed something / is there a better way?

http://ss64.com/ps/compare-object.html

推荐答案

没有该cmdlet的选项，但是您可以创建一个过滤器(例如在您的配置文件中)，然后使用它来过滤结果:像

there is no option like that for that cmdlet, however you could create a filter (in your profile for example) and then use it to filter the result : something like

filter leftside{
param(
        [Parameter(Position=0, Mandatory=$true,ValueFromPipeline = $true)]
        [ValidateNotNullOrEmpty()]
        [PSCustomObject]
        $obj
    )

    $obj|?{$_.sideindicator -eq '<='}

}

用法

compare-object $a $b | leftside

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