遇到DetailView时更新模型字段.[Django] [英] Update a Model Field when DetailView encounter. [Django]

问题描述

我在 views.py 中有一个DetailView:

I have a DetailView something like in views.py:

views.py

class CustomView(DetailView):
    context_object_name = 'content'
    model = models.AppModel
    template_name = 'dynamictemplate.html'

    def get_context_data(self, **kwargs):
        data = super(CustomView, self).get_context_data(**kwargs)
        <...snipped...>
        return data

当 urls.py 的请求转移到 views.py 时，如何更新模型字段( IntegerField ).假设IntegerField的名称为 clicks ，当用户访问特定链接或被动访问数据库中的模型对象时，该如何增加该对象的 clicks 字段通过1.

How could I update the model field, an IntegerField when the request from urls.py transfers to views.py. Let's suppose the name of IntegerField is clicks and when a user visits a particular link or passively, a model object from database, then how could I increment the clicks field of that object by 1.

推荐答案

您可以使用 self.object 并通过以下方式进行更新:

You can use self.object and update it this way:

self.object.clicks = self.object.clicks + 1
self.object.save()

但是正如丹尼尔(Daniel)在评论中所说，使用此代码，您可能会遇到 F表达式 像这样:

But as Daniel said in comment, using this code you can faced race condition. So it would be better to use F expressions like this:

from django.db.models import F

def get_context_data(self, **kwargs):
    data = super(CustomView, self).get_context_data(**kwargs)
    self.object.clicks = F('clicks') + 1
    self.object.save()
    <...snipped...>
    return data

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