Django:如何将字节对象保存到models.FileField? [英] Django: how save bytes object to models.FileField?

问题描述

我的Web应用程序具有以下结构:

My web application has the following structure:

1. 使用Django的后端
2. 使用React的前端.

我有一个与React的表格.我从客户端表单发送文件，并在我的Django应用程序中使用API​​View接收文件.

I have a form with React. I send a file from client form and I receive the file in my Django application with an APIView.

我收到一个m3u文件作为字节对象.

I receive a m3u file as bytes object.

b'------WebKitFormBoundaryIaAPDyj9Qrx8DrWA\r\nContent-Disposition: 
form-data; name="upload"; 
filename="test.m3u"\r\nContent-Type: audio/x- 
mpegurl\r\n\r\n#EXTM3U\n#EXTINF:-1 tvg-ID="" tvg-name="...

我会将Django模型中的文件保存到models.FileField并将bytes对象转换为m3u文件.你如何做到的?

I would save the file in a Django model to a models.FileField and convert bytes object to m3u file. How you do it?

推荐答案

1. models.FileField(models.ImageField)需要像对象一样的django.core.files.base.File例如)

1. models.FileField(models.ImageField) needs django.core.files.base.File like objects ex)

• django.core.files.images.ImageFile

• django.core.files.images.ImageFile

django.core.files.base.ContentFile

django.core.files.base.ContentFile

ImageFile或ContentFile需要两个参数.

ImageFile or ContentFile needs two args.

1. IO对象:具有seek()方法(例如io.BytesIO).

1. IO object : which has seek() method (ex) io.BytesIO).

name:str.(重要！没有名称，它将无法正常工作.)

name : str. (important! without name, it will not works).

bytes对象没有IO的方法(例如，seek()).应该将其转换为IO对象.

bytes object doesn't have IO's methods(ex) seek()). it should be converted to IO object.

models.py

models.py

    class Message(models.Model):
        image = models.ImageField(upload_to='message_image/%Y/%m', null=True)

views.py或consumers.py

views.py or consumers.py

    import io
    from django.core.files.images import ImageFile
    from myapp.models import Message
   
    def create_image_message(image_bytes):
        image = ImageFile(io.BytesIO(image_bytes), name='foo.jpg')  # << the answer!
        new_message = Message.objects.create(image=image)

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