其余框架& quot; get()缺少1个必需的位置参数" [英] rest-framework "get() missing 1 required positional argument"

问题描述

我想将GET参数'pk'传递给Django rest-framework.

I want transmit a GET parameters 'pk' to django rest-framework.

浏览器

但是在我的view.py中，我将GET方法设置为接收"pk"参数.

but in my view.py I was setting my GET method to receive ‘pk’ parameters.

views.py

这是urls.py代码:

It's urls.py code:

还有另一个问题，如果我在pycharm中使用'objects'方法对对象进行建模，则会抛出异常，例如:

and There is another one question,if I models object use 'objects' method in the pycharm,were throw an exception,such as:

但是我的朋友没有发生此异常.他使用pycharm 2017.4(macOS)

but my friend was not happen this exception. He use pycharm 2017.4(macOS)

cateloydata = category.objects.all()

我的pycharm版本:pycharm 2017.2python 3.6版django版本1.11.7

my pycharm version:pycharm 2017.2 python version 3.6 django version 1.11.7

谢谢大家.

很抱歉，发布图片需要至少10个声誉.因此，我的问题撰写非常糟糕.

and I'm sorry, I need at least 10 reputation to post images. So my question composing is very bad.

感谢！

推荐答案

在将参数添加到url时，必须在方法定义中添加一个额外的参数，如下所示:

When you are adding params to your url, you have to add an extra param to your method definition, like this:

# urls.py
url(r'^questions/(?P<pk>[\w:|-]+)/$', TheView.as_view(), name='view')

在上面的url中，您正在传递url参数(pk)，因此必须在方法中接收它:

In the url above, you are passing a url param (pk) so you have to receive it in the method:

# views.py
class TheView(APIView):
   def get(self, request, pk):
     ...

但是在您的情况下，您希望通过查询参数传递数据.

But in your case, you want to pass data by query params.

# urls.py
url(r'^questions/$', TheView.as_view(), name='view')

因此您不必在方法声明中接收它，请使用:

so you don't have to receive it in the method declaration, use:

def get(自身，请求):pk = request.GET.get('pk')

相反.

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