在Django中，如何将模块的url配置封装在模块内部? [英] In Django, how do you keep a module's url configurations encapsulated inside the module?

问题描述

当前，我使用以下命令将URL配置导入到我的Django项目中:

Currently, I import url configurations into my Django project with:

from django.conf.urls import include
from django.contrib import admin
from django.urls import path, re_path
from rest_framework import routers
from greeter.views import GreeterViewSet

ROUTER = routers.DefaultRouter()
ROUTER.register(r'greeters', GreeterViewSet)

urlpatterns = [
    path('admin/', admin.site.urls),
    re_path(r'^', include(ROUTER.urls)),
]

有没有一种方法可以移动代码的这些部分:

Is there a way where I can move these parts of the code:

ROUTER = routers.DefaultRouter()
ROUTER.register(r'greeters', GreeterViewSet)

放入 greeter/urls.py 中的单独文件?

并仍然保留以下网址:

• 获取/greeter/以获取问候者列表
• POST/greeter/创建一个新的问候者

我尝试过:

my_project/urls.py

my_project/urls.py

from django.conf.urls import include
from django.contrib import admin
from django.urls import path, re_path

urlpatterns = [
    path('admin/', admin.site.urls),
    re_path(r'^greeters/', include('greeter.urls')),
]

greeter/urls.py

greeter/urls.py

from django.conf.urls import url, include
from rest_framework import routers
from .views import GreeterViewSet

ROUTER = routers.DefaultRouter()
ROUTER.register(r'^', GreeterViewSet)

urlpatterns = [
    url(r'^', include(ROUTER.urls)),
]

但是得到了:

$ curl -H 'Accept: application/vnd.api+json; indent=2' -X POST http://localhost:8000/greeters/
{
  "errors": [
    {
      "detail": "Method \"POST\" not allowed.",
      "source": {
        "pointer": "/data"
      },
      "status": "405"
    }
  ]
}

以防万一，这是我原来的问题已解决:方法"POST"Django Rest Framework不允许使用

In case it helps, here is my original question that has been resolved: Method "POST" not allowed with Django Rest Framework

更新:

借助答案，我得以得出以下解决方案:

With the help of the answers, I was able to arrive at this solution:

my_project/urls.py

my_project/urls.py

from django.conf.urls import include
from django.contrib import admin
from django.urls import re_path

urlpatterns = [
    re_path('admin/', admin.site.urls),
    re_path('greeters/', include('greeter.urls')),
]

greeter/urls.py

greeter/urls.py

from django.conf.urls import include
from django.urls import re_path
from rest_framework import routers
from .views import GreeterViewSet

ROUTER = routers.DefaultRouter()
ROUTER.register(r'', GreeterViewSet)

urlpatterns = [
    re_path(r'', include(ROUTER.urls)),
]

与此:

• 所有迎接者网址配置均保存在迎接者内部模块
• 项目url配置将"greeter"资源与迎宾模块
• 似乎可以将其他问候者视图添加到迎宾者网址配置(我尚未对此进行测试)

我认为这是我所能得到的.再次感谢您提供的所有帮助:)

I think this is as good as I can get it. Thanks again for all of the help :)

推荐答案

正如我之前对您所说的，路由器需要一个前缀.您需要从主要网址中删除该前缀，并在路由器本身中使用它.

As I said to you before, the Router needs a prefix. You need to remove that prefix from your main URLs and use it in the router itself.

主要:

urlpatterns = [
    path('admin/', admin.site.urls),
    path('', include('greeter.urls')),
]

app:

ROUTER = routers.DefaultRouter()
ROUTER.register(r'^greeter/', GreeterViewSet)

urlpatterns = ROUTER.urls

(由于路由器路由器没有其他URL，因此不需要在其中使用include，您可以直接使用路由器URL.)

(Since you don't have any URLs other than the router ones, you don't need to use include there, you can just use the router urls directly.)

还请注意，这几乎可以肯定不是您想要做的全部；这意味着除了视图集的URL之外，您再也没有其他任何URL.

Also note, this whole thing is almost certainly not what you want to do; it means you can never have any URLs other than those for your viewset.

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