如何验证object.create()方法的选择? [英] How to validate CHOICES for objects.create() method?

问题描述

我有以下模型:

from django.db import models


class Artist(models.Model):

    TYPE_CHOICES = (
        ('Person', 'Person'),
        ('Group', 'Group'),
        ('Other', 'Other'),)

    name = models.CharField(max_length=100)
    type = models.CharField(max_length=20, choices=TYPE_CHOICES)

问题是，如果我创建这样的对象: Artist.objects.create(...)类型验证无效.我该如何激活验证?

The problem is that if I create an object like this: Artist.objects.create(...) the type validation doesn't work. How can I activate the validation for this?

推荐答案

您可以创建一个(抽象的)模型，该模型首先执行验证，然后使用以下方法保存对象:

You can make an (abstract) model that first performs validations before saving the object with:

class ValidatedModel(models.Model):

    class Meta:
        abstract = True

    def save(self, *args, **kwargs):
        self.clean_fields()      # validate individual fields
        self.clean()             # validate constraints between fields
        self.validate_unique()   # validate uniqness of fields
        return super(ValidatedModel, self).save(*args, **kwargs)

然后例如在以下模型中使用它:

and then for example use this in models like:

class Artist(ValidatedModel):

    TYPE_CHOICES = (
        ('Person', 'Person'),
        ('Group', 'Group'),
        ('Other', 'Other'),)

    name = models.CharField(max_length=100)
    type = models.CharField(max_length=20, choices=TYPE_CHOICES)

请注意，如果您调用 .save()方法(或某些其他函数执行此操作)，则上述内容将验证模型对象，但是某些方法会规避调用 .save()的情况.方法，例如 Model.objects.bulk_create(..)等.

Note that the above will validate model object in case you call the .save() method (or some other function does that), but some methods circumvent calling the .save() method like Model.objects.bulk_create(..), etc.

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