谷歌地图时区获取本地时间 [英] google map Time Zone get local time

问题描述

我尝试使用谷歌时区API。我公司提供的经度和纬度和API给我的时区。

I'm trying to use google Time Zone API. I provide the longitude and latitude and the API give me the timezone.

我怎样才能获得本地时间与此下面的值（字符dstOffset和rawOffset）？

How can I get the local time with this following value (dstOffset and rawOffset) ?

下面是JSON的

{
   "dstOffset" : 0.0,
   "rawOffset" : -28800.0,
   "status" : "OK",
   "timeZoneId" : "America/Los_Angeles",
   "timeZoneName" : "Pacific Standard Time"
}

我已经试过这个javascript函数，但我没有得到正确的时间。

I have tried this javascript function but I don't get the correct time.

function calcTime(offset) {
    var d = new Date();
    var utc = d.getTime() + (d.getTimezoneOffset() * 60000);
    var nd = new Date(utc + (3600000*offset));

    alert("The local time is " + nd.toLocaleString());
}

calcTime(-28800.0);

感谢您的帮助！

推荐答案

您正在接近。问题是在这一行：

You're close. The problem is in this line:

var nd = new Date(utc + (3600000*offset));

偏移量由JSON的给予似乎是秒;你对待它，就好像它是在小时。它更改为以下，它应该开始工作：

The offset given by the Json appears to be in seconds; you are treating it as though it is in hours. Change it to the following and it should start working:

var nd = new Date(utc + (1000*offset));

下面是工作的jsfiddle 。

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