从ManyToManyField DRF序列化一个字段 [英] Serializing one field from a ManyToManyField DRF

问题描述

我有很多帖子，DRF文档(需要很多的爱)，而且我还找不到没有复杂混乱的方法.

I have been lot of posts, the DRF documentation (which needs LOT of love), and I couldn't find yet how to do this without a complicated mess.

我需要以下输出:

[{"id":1,"name":"memcheck","subscribers":["foo", "bar"]}]

如果我采用DRF方式(或者至少是文档指出我的方式)，那么我会得到以下输出:

If I go with the DRF way (or at least how the docs point me how to do it), then I get this output:

[{"id":1,"name":"memcheck","subscribers":["Subscriber object", "Subscriber object"]}]

我尝试取消注释并使用第二个选项，然后得到以下输出:

I tried uncommenting and going with a second option, then I get this output:

[{"id":1,"name":"memcheck","subscribers":[{"name": "foo"}, {"name": "bar"}]}]

models.py

class Subscriber(models.Model):
    name = models.CharField(max_length=100)


class Check(models.Model):
   name = models.CharField(max_length=100)
   description = models.TextField(null=True, blank=True)
   subscribers = models.ManyToManyField(Subscriber)

serializers.py

class SubscriberSerializer(serializers.ModelSerializer):
    name = serializers.CharField()

    class Meta:
        fields = ('name', )


class CheckSerializer(serializers.ModelSerializer):
    # using source=('name') or variants like: 'subscribers__name', 'subscribers.name' 
    # doesnt work
    subscribers = serializers.ListSerializer(child=serializers.CharField())
    # subscribers = SubscriberSerializer(many=True) # --> see 2nd output

    class Meta:
        model = Check
        fields = ('id', 'name', 'subscribers')

在ManyToMany的其他情况下，我希望有字典列表，但是在这种情况下，我只想要一个简单的列表，其名称为attr ..为什么这样做太难了?

In other cases of ManyToMany I would like to have the list of dict, but in this case I just want a simple list with the name attr.. why is too hard to do it?

推荐答案

您只需要 SlugRelatedField :

class CheckSerializer(serializers.ModelSerializer):

    subscribers = serializers.SlugRelatedField(many=True, read_only=True, slug_field='name')

    class Meta:
        model = Check
        fields = ('id', 'name', 'subscribers')

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