如何将django表单呈现为html(不在模板中) [英] How to render django form into html (not in template)

问题描述

我有一个模板在其中

<div id="form-wrapper">
    {{form}}
</div>

现在，如果用户提交(通过 AJAX )并且出现错误，我想做

Now if the user submits (via AJAX) and there are errors, I want to do

$(#form-wrapper").html(data.form);

基本上只需替换整个表单即可显示错误.但是当我写

Basically just replace the whole form to show the errors. But when I write

返回JsonResponse({'form':form})

告诉我我的表单不可序列化.说得通.所以我的问题是:django如何将表单呈现为html?我应该调用什么功能?

in the view django tells me that my form isn't serializable. Makes sense. So my question is: how does django render forms into html? What function should I call?

注意:我知道我可以只返回错误而不是整个表单，但这需要在模板中添加更多js代码才能将每个字段的错误放在正确的位置.我想要django在说 {{form}} 时使用的一个功能.

Note: I know I can return just the errors instead of the whole form, but that would require more js code in the template to put each field's errors in the correct place. I want the one function that django uses when I say {{form}}.

谢谢！

推荐答案

在与任何对象一起显示时，所有模板所做的全部操作称为 str()(或 unicode()) 在上面.在内部，在form类上实现这些方法的方法仅委托给 as_table()方法.因此，您可以直接致电:

All the template does when presented with any object is call str() (or unicode()) on it. Internally, the methods that implement those on the form class simply delegate to the as_table() method. So you can just call that directly:

return JsonResponse({'form': form.as_table()})

但是请注意，您可能想添加其他HTML，在这种情况下，更好的方法可能是使用 render_to_string 将一个简单的模板片段(包括表单)简单呈现为字符串-并在Json响应中发送.

Note, though, that you might want to add other HTML, in which case a better approach might be to simply render a short template snippet, including the form, to a string - using render_to_string - and send that in the Json response.

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