我的models.py有什么问题 [英] what wrong with my models.py

问题描述

我将Django 1.4与PostgreSQL 9.1.4一起使用

I am using Django 1.4 with PostgreSQL 9.1.4

我的模型有什么问题.py

what wrong with my models.py

class UserProfile(models.Model):
    ROLES_TYPE = (
        ('Employee', 'Employee'),
        ('Employor', 'Employor'),
    )
    user = models.OneToOneField(User, related_name='Profile')
    role = models.CharField(max_length=15, choices=ROLES_TYPE)

class Student(models.Model):
    id = models.AutoField(db_column='studentid', primary_key=True)
    username = models.OneToOneField(UserProfile, related_name='Employee')
    first_name = models.CharField(db_column='fname', max_length=100,
                              null=True, blank=True)
    last_name = models.CharField(db_column='lname', max_length=100,
                             null=True, blank=True)

当我运行./manage.py syncdb时，出现了错误

When I run ./manage.py syncdb , i got error

Creating tables ...
Creating table Student
Traceback (most recent call last):
  File "manage.py", line 10, in <module>
    execute_from_command_line(sys.argv)
  File "/home/jayapaldharmamani/Projects/jayapal/aplink/aplink_env/local/lib/python2.7/site-packages/django/core/management/__init__.py", line 443, in execute_from_command_line
utility.execute()
  File "/home/jayapaldharmamani/Projects/jayapal/aplink/aplink_env/local/lib/python2.7/site-packages/django/core/management/__init__.py", line 382, in execute
self.fetch_command(subcommand).run_from_argv(self.argv)
  File "/home/jayapaldharmamani/Projects/jayapal/aplink/aplink_env/local/lib/python2.7/site-packages/django/core/management/base.py", line 196, in run_from_argv
    self.execute(*args, **options.__dict__)
  File "/home/jayapaldharmamani/Projects/jayapal/aplink/aplink_env/local/lib/python2.7/site-packages/django/core/management/base.py", line 232, in execute
    output = self.handle(*args, **options)
  File "/home/jayapaldharmamani/Projects/jayapal/aplink/aplink_env/local/lib/python2.7/site-packages/django/core/management/base.py", line 371, in handle
    return self.handle_noargs(**options)
  File "/home/jayapaldharmamani/Projects/jayapal/aplink/aplink_env/local/lib/python2.7/site-packages/django/core/management/commands/syncdb.py", line 102, in handle_noargs
    cursor.execute(statement)
  File "/home/jayapaldharmamani/Projects/jayapal/aplink/aplink_env/local/lib/python2.7/site-packages/django/db/backends/util.py", line 40, in execute
    return self.cursor.execute(sql, params)
  File "/home/jayapaldharmamani/Projects/jayapal/aplink/aplink_env/local/lib/python2.7/site-packages/django/db/backends/postgresql_psycopg2/base.py", line 52, in execute
    return self.cursor.execute(query, args)
django.db.utils.DatabaseError: column "id" referenced in foreign key constraint does not exist

删除相关名称和ID字段后的SQL查询

SQL Query after removing related names and ID field

创建表"admin_userprofile"(

CREATE TABLE "admin_userprofile" (

 "id" serial NOT NULL PRIMARY KEY,
       "user_id" integer NOT NULL UNIQUE REFERENCES "auth_user" ("id") DEFERRABLE     INITIALLY DEFERRED,
        "role" varchar(15) NOT NULL
    );

创建表格学生"(

       "id" serial NOT NULL PRIMARY KEY,
       "username_id" integer NOT NULL UNIQUE REFERENCES "admin_userprofile" ("id") DEFERRABLE INITIALLY DEFERRED
    );

请帮助我.

感谢&问候，Jayapal D

Thanks & Regards, Jayapal D

推荐答案

这是由数据库而不是django本身生成的问题.尝试重新创建数据库架构(您只需删除所有相关列并执行 ./manage.py syncdb .

This is a problem generated by your database not django itself. Try to recreate your database schema (you can just remove all related columns and execute ./manage.py syncdb.

这篇关于我的models.py有什么问题的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！