如何仅在django中为某些路径定义中间件? [英] how to define middleware only for certain paths in django?

问题描述

有没有在Django中为特定的路由或路由组定义中间件?就像laravel一样，我们可以将其定义如下:

is there anyway to define middleware for specific route or route groups in django? like laravel which we can define it as follows:

Route :: get('admin/profile'，function(){})-> middleware('auth');

推荐答案

从历史上看，您可以利用一些钩子来执行类似的操作.但是如今，您可以肯定要重写:

Historically there have been a few hooks you can exploit to do something like this. But nowadays you can for sure override:

def process_view(self, request, view_func, view_args, view_kwargs):
     ...

在您的中间件类中，然后您可以从 request.path 解析视图/路由，并调度自定义逻辑(如果匹配或不匹配)，或者可以匹配 view_func .__ name __ 或类似的名称，等等.这取决于您的需求.

in your middleware class and then you could resolve the view/route from request.path and dispatch custom logic if it matches or not, or you could match over view_func.__name__ or something similar, etc. Depends on your needs.

https://docs.djangoproject.com/zh/2.0/topics/http/middleware/#process-view

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