如何仅使用CMD命令传递选项? [英] How to pass only options with the CMD command?

问题描述

假设我的控件之外有一个图像指定了自定义入口点.我们称之为 server

Suppose there's an image outside of my control that specifies custom entry point. Let's call it server

# server's Dockerfile

ENTRYPOINT /usr/bin/server

我正在基于服务器构建映像.我想指定要执行的默认命令.它应该调用服务器的入口点并向其传递参数.该参数是一个选项.一个幼稚的解决方案看起来像这样:

I'm building an image based on the server. I'd like to specify a default command to be executed. It should call the server's entrypoint and pass an argument to it. The argument is a single option. A naive solution would look like this:

FROM server:latest

CMD --port 8080

但是，这在 docker build 与

Error response from daemon: Dockerfile parse error line 3: Unknown flag: port

如何使用CMD将参数传递给以-开头的入口点?

How can I use CMD to pass arguments to entry point that start with --?

推荐答案

命令定义如下:

CMD [ "--port", "8080" ]

否则，将-port 作为标志附加到CMD命令本身，而不是它实际运行的命令.

Where otherwise the --port gets attached to the CMD command itself as a flag, not the actual command it runs.

这假定 ENTRYPOINT 只能正确处理选项，并且不需要像传统情况那样需要可执行文件的路径.

This presumes that the ENTRYPOINT can properly handle just options and doesn't require a path of an executable as is traditionally the case.

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