程序集连接两个字符串 [英] assembly concatenate two strings

问题描述

我想连接两个字符串，但是在输出中而不是得到最终的连接字符串，我得到了一行奇怪的字符和空格，也许有人可以帮我一点忙.我想将结果保存在s3中.这是代码

I want to concatenate two strings but in my output instead of getting the final concatenated string, I get a line of weird characters and spaces, maybe someone could help me a bit. I want to save the result in s3. Here is the code

DATA SEGMENT
    STR1 DB "ENTER FIRST STRING HERE ->$"
    STR2 DB "ENTER SECOND STRING HERE ->$"
    STR3 DB "CONCATEnatedD STRING :->$"
    STR11 DB "FIRST STRING : ->$"
    STR22 DB "SECOND STRING: ->$"

    s1 DB 20 DUP("$")
    s2 DB 20 DUP("$")
    s3 db 40 dup(?)
    NEWLINE DB 10,13,"$"

DATA ENDS

CODE SEGMENT

    ASSUME DS:DATA,CS:CODE
START:

    MOV AX,DATA
    MOV DS,AX


lea dx,str1
mov ah,09h
int 21h

lea si,s1

l1: mov ah,01h
int 21h

mov [si],al
inc si
cmp al,31h
jne l1

dec si

lea dx,str2
mov ah,09h
int 21h

lea di,s2

l2: mov ah,01h
int 21h

mov [di],al
inc di
cmp al,32h
jnz l2

lea si,s3
lea di,s1


lea si,s3
lea di,s1
l3: mov al,[di]
mov [si],al
inc si
inc di
cmp al,31h
jnz l3

dec si

lea di,s2

l4: mov al,[di]
mov [si],al
inc si
inc di
cmp al,32h
jnz l4

lea dx,str3
mov ah,09h
int 21h

l5: mov dl,[si]
cmp dl,32h
jz l6
mov ah,02h
int 21h
inc si
jmp l5


l6:MOV AH,4CH
    INT 21H


CODE ENDS
END START

我找到了解决方案，希望它是一个不错的解决方案，不会出现任何错误:数据段msg db 0Dh，0Ah，"String1:$"msg2 db 0Dh，0Ah，字符串2:$"rev db 0Dh，0Ah，结果:$"

I have found the solution, hope it is a good one without any mistake: data segment msg db 0Dh, 0Ah, "String1: $" msg2 db 0Dh, 0Ah, "String2: $" rev db 0Dh, 0Ah, "Result: $"

buffer label byte  
buffer2 label byte
str_maxlen db 255
str_length db 0

str_string db 255 dup(0)
str_string2 db 255 dup(0)
result db 255 dup('$')
num db 0
data ends

code segment
assume cs:code, ds:data
start:
mov ax,data
mov ds,ax

lea dx,msg
mov ah,09h
int 21h

lea dx,buffer
mov ah,0Ah
int 21h

mov cl,str_length
mov bh,cl
mov ch,0
lea si,str_string
lea di,result

op1:    mov bl,[si]
mov [di],bl
inc di
inc si
loop op1

mov cl,bh
op3:    dec si
loop op3

lea dx,msg2
mov ah,09h
int 21h

lea dx,buffer2
mov ah,0Ah
int 21h
mov cl,str_length

lea si,str_string
mov cl,str_length

mov ax,0
op2:    mov al,[si]
mov [di],al
inc di
inc si
loop op2

lea dx,rev
mov ah,09h
int 21h

lea dx,result
mov ah,09h
int 21h

mov ah,4Ch
int 21h
code ends

end start

推荐答案

在您的第一个代码中，您必须设置 si 指向字符串 s3 就在标签 l5:之前(因为 si 指向循环 l4之后的 s3 的结尾:):

In your first code, you have to set si to point to the beginning of string s3 right before label l5: (because si was pointing to the end of s3 after loop l4:) :

.
.
.
lea dx,str3
mov ah,09h
int 21h

lea si,s3          ;◄■■■■■■■■■■■  
l5: mov dl,[si]
cmp dl,32h
jz l6
.
.
.

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