与in运算符%in%一起使用mutate_at [英] using mutate_at with the in operator %in%
问题描述
我有一个带有一些变量的数据框以反转代码.我有一个单独的向量,其中包含所有要反转代码的变量.我想使用mutate_at()或其他一些简洁的方法,以一行代码将它们全部反向编码.这是数据集和要反转的项的向量
I have a data frame with a few variables to reverse code. I have a separate vector that has all the variables to reverse code. I'd like to use mutate_at(), or some other tidy way, to reverse code them all in one line of code. Here's the dataset and the vector of items to reverse
library(tidyverse)
mock_data <- tibble(id = 1:5,
item_1 = c(1, 5, 3, 5, 5),
item_2 = c(4, 4, 4, 1, 1),
item_3 = c(5, 5, 5, 5, 1))
reverse <- c("item_2", "item_3")
这就是我想要的样子,仅将项目2和3反向编码:
Here's what I want it to look like with only items 2 and 3 reverse coded:
library(tidyverse)
solution <- tibble(id = 1:5,
item_1 = c(1, 5, 3, 5, 5),
item_2 = c(2, 2, 2, 5, 5),
item_3 = c(1, 1, 1, 1, 5))
我已经在下面的代码中尝试过了.我知道该重新编码是正确的,因为我已将其用于其他数据集,但是我知道%in%运算符有些问题.
I've tried this below code. I know that the recode is correct because I've used it for other datasets, but I know something is off with the %in% operator.
library(tidyverse)
mock_data %>%
mutate_at(vars(. %in% reverse), ~(recode(., "1=5; 2=4; 3=3; 4=2; 5=1")))
Error: `. %in% reverse` must evaluate to column positions or names, not a logical vector
任何帮助将不胜感激!
推荐答案
您可以直接将 reverse
赋予 mutate_at
,而无需 vars(.%in%反向)
.而且我会将反转简化为6减去当前值.
You can give reverse
directly to mutate_at
, no need for vars(. %in% reverse)
. And I would simplify the reversing as 6 minus the current value.
mock_data %>% mutate_at(reverse, ~6 - .)
# # A tibble: 5 x 4
# id item_1 item_2 item_3
# <int> <dbl> <dbl> <dbl>
# 1 1 1 2 1
# 2 2 5 2 1
# 3 3 3 2 1
# 4 4 5 5 1
# 5 5 5 5 5
如果 reverse
可能包含不在 mock_data
中的列,而您想跳过这些列,请使用 mutate_at(vars(one_of(reverse)),...)
If there's a possibility that reverse
includes columns that are not in mock_data
, and you want to skip those, use mutate_at(vars(one_of(reverse)), ...)
这篇关于与in运算符%in%一起使用mutate_at的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!