如何在r中创建新列，该列是基于字符串变量的二项式变量? [英] How do I create a new column in r that is a binomial variable based on a string variable?

问题描述

我目前正在尝试使用mutate()在另一列的基础上在数据框中创建新列.

I'm currently trying to create a new column in my data frame based on another column using mutate().

我要基于新列是否表示活动"，将新列设为二项式变量(1或0).我目前正在尝试通过说:

I want to make the new column a binomial variable (1 or 0) based on whether the column its based on says "Active" or not. I'm currently trying to do it by saying:

violations$outcome = if (violations$RESULT == "Active") { 1 } else { 0 }

这当前会产生警告消息:在if(violations $ RESULT ==活跃的老鼠迹象"){:条件的长度> 1，并且只会使用第一个元素"，然后查看新数据框，每个 violations $ outcome 均为0.

This currently produces the "Warning message: In if (violations$RESULT == "Active Rat Signs") { : the condition has length > 1 and only the first element will be used" and I look at my new data frame and every violations$outcome is 0.

有人知道如何执行此操作以及为什么我的原始答案无效吗?这非常令人沮丧，如果您有任何意见，建议或帮助，我将不胜感激.谢谢.

Does anyone have any idea how to do this and why my original answer isn't working? This is very frustrating and I would appreciate any comments, advice, or help you have to offer. Thank you.

推荐答案

R有一个方便的函数，称为 ifelse

R has a handy function called ifelse

尝试 violations $ outcome = ifelse(violations $ RESULT =='Active'，1，0).第一个参数是要测试的条件，第二个参数是 TRUE 时返回的内容，第三个参数是 FALSE 时返回的内容.

Try violations$outcome = ifelse(violations$RESULT == 'Active', 1, 0). The first argument is the condition you're testing, the second argument is what to return if it is TRUE and the third agrument is what to return if it's FALSE.

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