我的Java应用程序无法读取我的文件(Maven项目) [英] My java application does not read my files (maven project)

问题描述

我在一个Java简单项目中有一个应用程序.但是，我需要将此项目粘贴到Maven项目中.因此，我基本上做了一个简单的Maven项目，然后将所有类复制并粘贴到该项目中.我需要在服务器上运行war，并且需要像Java应用程序一样运行Main，因为此应用程序配置了war应用程序.但是，当我运行Main时，遇到了一些以前没有的错误:

I have an application in a Java simple project. However, I need to paste this project to a Maven project. So, I basically made a simple Maven project, and I copied and pasted all my classes into it. I need a war to run in a server, and I need to run a Main like a Java application, because this application configures the war application. However, when I run Main, I get some errors that I wasn't having before:

java.io.FileNotFoundException:resources \ config.properties(系统找不到指定的路径)

java.io.FileNotFoundException: resources\config.properties (The system cannot find the path specified)

代码中的时间是:

input = new FileInputStream("resources/config.properties");

这也不起作用:

faceDetector = new CascadeClassifierDetector("D:/retinoblastoma/workspace/Resources/CascadeClassifiers/FaceDetection/haarcascade_frontalface_alt.xml");

我该如何解决?

推荐答案

如果您使用的是简单的maven项目"，则maven的方法是使用 src/main/resources 文件夹.您是否将pom.xml配置为执行其他操作?

If you're using a "simple maven project", the maven way is for there to be a src/main/resources folder. Did you configure your pom.xml to do something different than that?

如果您正确完成了jar创建部分，则获取位于类路径上的文件的正确方法是:

If you've done the jar creation portion correctly, the right way to get a file that's on the classpath is:

getClass().getResourceAsStream("/path/to/resource.ext");

正斜杠很重要！

如果文件不在您的类路径中(换句话说，如果上面的方法不起作用，则可能是这种情况)，您可能需要将maven配置为使用其他资源目录.

If the file is NOT on your classpath (in other words, this will be the case if the above doesn't work), you probably need to configure maven to use a different resources directory.

您可以按这样做(适当地更改参数):

You do that like this (change the arguments as appropriate):

<build>
  ...
  <resources>
    <resource>
      <targetPath>META-INF/plexus</targetPath>
      <filtering>false</filtering>
      <directory>${basedir}/src/main/plexus</directory>
      <includes>
        <include>configuration.xml</include>
      </includes>
      <excludes>
        <exclude>**/*.properties</exclude>
      </excludes>
    </resource>
  </resources>
  <testResources>
    ...
  </testResources>
  ...
</build>

然后，您的文件将位于您的类路径中，并且上面的代码将起作用.阅读上面链接的文档以获取更多信息.

Then, your file will be on your classpath and the above code will work. Read the linked documentation above for more information.

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