为什么此方法引用在运行时失败,但没有相应的lambda调用失败? [英] Why is this method reference failing at runtime but not the corresponding lambda call?
问题描述
我有这两个界面.一个是公共(A),另一个是包私有(AA). A
扩展了 AA
.
I have these two interfaces. One is public (A), the other one is package private (AA). A
extends AA
.
package pkg.a;
@FunctionalInterface
public interface A extends AA {
}
.
package pkg.a;
interface AA {
default void defaultM() {
System.out.println(m());
}
String m();
}
我有此代码(在其他包装中):
I have this code (in a different package):
package pkg;
import java.util.Arrays;
import java.util.List;
import pkg.a.A;
public class Test {
public static void main(String[] args) {
List<A> list = Arrays.asList(() -> "imp1", () -> "imp2");
list.stream().forEach(a -> a.defaultM());
list.stream().forEach(A::defaultM);
}
}
运行上面的代码时, list.stream().forEach(A :: defaultM);
引发以下异常.为什么?为什么lambda表达式可以,但是方法引用为什么不能访问package-private接口中定义的方法?我正在Java版本1.8.0_191的Eclipse(版本:2018-12(4.10.0))中运行它.
When running the above code the list.stream().forEach(A::defaultM);
throws the below exception. Why? Why can't the method reference access the methods defined in the package-private interface while the lambda expression can? I'm running this in Eclipse (Version: 2018-12 (4.10.0)) with Java version 1.8.0_191.
imp1
imp2
Exception in thread "main" java.lang.BootstrapMethodError: call site initialization exception
at java.lang.invoke.CallSite.makeSite(CallSite.java:341)
at java.lang.invoke.MethodHandleNatives.linkCallSiteImpl(MethodHandleNatives.java:307)
at java.lang.invoke.MethodHandleNatives.linkCallSite(MethodHandleNatives.java:297)
at pkg.Test.main(Test.java:14)
Caused by: java.lang.IllegalArgumentException: java.lang.IllegalAccessException: class is not public: pkg.a.AA.defaultM()void/invokeInterface, from pkg.Test
at java.lang.invoke.MethodHandles$Lookup.revealDirect(MethodHandles.java:1360)
at java.lang.invoke.AbstractValidatingLambdaMetafactory.<init>(AbstractValidatingLambdaMetafactory.java:131)
at java.lang.invoke.InnerClassLambdaMetafactory.<init>(InnerClassLambdaMetafactory.java:155)
at java.lang.invoke.LambdaMetafactory.metafactory(LambdaMetafactory.java:299)
at java.lang.invoke.CallSite.makeSite(CallSite.java:302)
... 3 more
Caused by: java.lang.IllegalAccessException: class is not public: pkg.a.AA.defaultM()void/invokeInterface, from pkg.Test
at java.lang.invoke.MemberName.makeAccessException(MemberName.java:850)
at java.lang.invoke.MethodHandles$Lookup.checkAccess(MethodHandles.java:1536)
at java.lang.invoke.MethodHandles$Lookup.revealDirect(MethodHandles.java:1357)
... 7 more
推荐答案
这是一个错误:
对在包访问类中声明的方法的引用(通过public subtype)编译为lambda桥;符合条件的类型bridge方法是声明类,而不是引用的类.这会导致一个IllegalAccessError.
A reference to a method declared in a package-access class (via a public subtype) compiles to a lambda bridge; the qualifying type in the bridge method is the declaring class, not the referenced class. This leads to an IllegalAccessError.
已在Java 9中修复.
Fixed in Java 9.
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