从YouTube API显示输出XML - PHP [英] display xml output from youtube api - php

问题描述

我发现我可以通过观看次数（命中）的YouTube频道的视频列表，并与下方

i've found that I can get a list of a youtube channel's videos by viewCount (hits) and limit the results with the link below

<一个href=\"http://gdata.youtube.com/feeds/api/users/edbassmaster/uploads?orderby=viewCount&max-results=5\" rel=\"nofollow\">http://gdata.youtube.com/feeds/api/users/edbassmaster/uploads?orderby=viewCount&max-results=5

这当然会返回一些XML饲料code。我想列出的视频上传到我的一个div网站。

this of course returns some xml feed code. I am trying to list the videos onto my website in a div.

我已经试过：

<?php
    $list = Array(); 
    //get the xml data from youtube 
    $url = "http://gdata.youtube.com/feeds/api/users/edbassmaster/uploads?orderby=viewCount&max-results=5"; 
    $xml = simplexml_load_file($url); 
    //load up the array $list['title'] = $xml->title[0]; 
    $list['title'] = $xml->title[0]; 
    echo $list['title'];
?>

到目前为止，这只是给我的标题XML饲料，如果我尝试 $ XML的＆GT;标题[1] 。它不返回任何东西。我如何使用XML提要列出标题和（HREF）其链接到视频？我尝试从XML源2件事，视频和URL的名称。

So far that just gives me the title for the xml feed, if I try $xml->title[1]. It doesn't return anything. How can I use that xml feed to list the titles and (href) link them to the videos? I'm trying to retrieve 2 things from the xml source, the title of the video and the url.

感谢。

推荐答案

事情是这样的：

 <?php
$url = "http://gdata.youtube.com/feeds/api/users/edbassmaster/uploads?orderby=viewCount&max-results=5";
$xml = simplexml_load_file($url);
foreach($xml->entry as $entry){
    echo "Title: ".$entry->title."<br />";
    echo "Link :".$entry->link['href']."<br />";
}
?>

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