如何在Elixir中替换数组中的元素 [英] How to replace elements in an array in elixir

问题描述

我想用3替换所有出现的2.我想这样做而不使用索引的值，因为那将是硬编码.到目前为止，我有:

I want to replace all occurrences of 2 with 3.I want to do this without using the value of the index because that would be hardcoding. What I have so far is:

list=[1,2,3,4,2,34,2]

replace_at(list, index, value)

Enum.each list, fn(x) ->
if x==2 do
  replace_at(list, index, 3)
end

Enum.each list, fn(x) ->
IO.puts x
end

推荐答案

在Elixir中，您没有数组，但是地图 Enum 模块的

In Elixir, you do not have arrays, but linked list. If you simply want to replace all ocurrences of 2 with 3, you can use the map function, of the Enum module like this:

iex(1)> Enum.map(list, fn x -> if x == 2, do: 3, else: x end)
[1, 3, 3, 4, 3, 34, 3]

您还可以使用模式匹配:

You could also use pattern matching:

iex(1)> Enum.map(list, fn
...(1)> 2 -> 3
...(1)> x -> x
...(1)> end)

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